let f ð p þ be the number of fixed points of p 2 s3 ¼ fð 1 2 3 þ
Báo cáo toán học: "The Number of Permutation Binomials Over F4p+1 where p and 4p + 1 are Primes" doc
... of combinatorics 13 (20 06), #R65 13 q 13 29 53 14 9 17 3 26 9 29 3 31 7 38 9 509 557 6 53 7 73 797 p N1 13 37 16 43 20 67 36 73 28 79 12 97 48 12 7 40 13 9 56 16 3 52 19 3 64 19 9 72 N2 0 16 20 24 28 32 36 ... ≡ 1 2 (p − 1) + N1 + N2 2 (p − 1) + N1 + N2 2N1 2N2 2 (p − 1) + N1 + N2 2 (p − 1) + N1 + N2 2N2 2N1 Proof We only prove one of the cases since the proofs of the remaining cases are similar Suppose ... p 1 p ≡ 1 2 (p − 1) + N2 2 (p − 1) + N2 N1 N2 2 (p − 1) + N1 2 (p − 1) + N1 N2 N1 the electronic journal of combinatorics 13 (20 06), #R65 12 (3) If 3p < m < 4p then (mod 4) m 1 m 2 m 3 m≡4 p 1 p...
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Báo cáo toán học: "The Number of Labeled 2-Connected Planar Graphs" ppsx
... 718 117 18 414 0 617 8 927 16 8985 5 23 5 722 63 526 78 724 29 720 , for q = 50 The approximation becomes less accurate when q/n approaches the q/n 13 / 12 14 / 12 15 / 12 16 / 12 17 / 12 18 / 12 19 / 12 20/ 12 21/ 12 22/ 12 23/ 12 24/ 12 25/ 12 26/ 12 27/ 12 ... 40950 20 545 920 57 12 15 33 7560 719 37 60 1 922 760 22 34 40 20 16 0 997 920 14 757 12 0 10 36 929 60 4 23 918 4 32 11 19 730 0 32 2 014 030 656 25 16 8 83 516 21 816 61 020 12 8 537 7660 49 12 8 2 820 10 990 728 0 10 929 600 10 18 1440 12 7 00800 ... 1 7 23 18 098 5 23 626 0 1. 30 5 20 4 31 5 117 35 945 8 13 6 1. 4 41 21 820 18 76 529 84 3 21 6 1. 600 22 11 95856 014 47 629 40 1. 796 23 13 434 0 527 97 31 4 820 2. 049 24 11 607 530 825 38 8960 2. 39 0 25 764607 530 0445 12 0 2. 877 26 37 70 6 23 31 3 530 920 ...
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Báo cáo hóa học: "ON THE SYSTEM OF RATIONAL DIFFERENCE EQUATIONS xn+1 = f (yn−q ,xn−s ), yn+1 = g(xn−t , yn− p )" ppt
... ,M2 = M2 ≤ M2 2 (2. 18 ) From (i) and (2. 18 ) we obtain m1 = f M2 ,m0 ≤ f M2 ,m1 = m2 , 1 1 1 m2 = f M2 ,m1 ≤ f m1 ,M1 = M1 , 1 2 1 M1 = f m1 ,M1 ≤ f m0 ,M1 = M1 , 2 m1 = g M1 ,m0 ≤ g M1 ,m1 = m2 ... = f mi2 1 ,M1 1 , i mi1 = f M2 1 ,mi1 1 , i i M2 = g mi1 1 ,M2 1 , i mi2 = g M1 1 ,mi2 1 (2. 17 ) It is easy to verify that 0 m0 ≤ m1 = f M2 ,m0 ≤ f m0 ,M1 = M1 ≤ M1 , 1 0 m0 ≤ m1 = g M1 ,m0 ≤ ... M1 = f m2 ,M1 , M2 = g m1 ,M2 , m2 = g M1 ,m2 , m1 = f M2 ,m1 (2. 25) Using assumption (ii), it follows from (2. 23) that lim xn = m1 = M1 = S, n→∞ lim yn = m2 = M2 = T n→∞ (2. 26) Theorem 2. 2...
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Báo cáo toán học: "The number of F -matchings in almost every tree is a zero residue" ppt
... between the vertex ul +1 of the i’th copy and the vertex u1 of the (i + 1) ’th copy We think of the first copy of u1 as the root of Wt′ Let P ′ be the path connecting the first copy of u1 with the last ... of t copies of F in which we identify the vertex ul +1 of copy i with the vertex u1 of copy i + (for ≤ i ≤ t − 1) Let P ⊂ Wt be the path in Wt connecting the first copy of u1 to the last copy of ... copy of ul +1 , and number its vertices by 1, , lt + in the natural order, from the copy of u1 in the first copy of F to the copy of ul +1 in the last copy of F We want to have a direction of parenthood...
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Báo cáo y học: " Alarms in the intensive care unit: how can the number of false alarms be reduced" doc
... 19 98 : 13 3 13 9 17 AARC Clinical Practice Guideline: Capnography/capnometry during mechanical ventilation Respir Care 19 95, 40: 1 3 21 1 32 4 18 AARC Clinical Practice Guideline: Pulse oximetry Respir ... values for SpO2 and on the transcutaneous partial pressure of O2 (PtcO2) is not justified, even if these alarm settings are otherwise justified for the preterm infant It is therefore possible ... Care Med 20 00, 28 :15 65 15 68 23 Rheineck-Leyssius AT, Kalkman CJ: Influence of pulse oximeter settings on the frequency of alarms and detection of hypoxemia: theoretical effects of artifact rejection,...
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Báo cáo y học: "The association of meat intake and the risk of type 2 diabetes may be modified by body weight"
... 51. 3 23 .9 23 .9 0. 81 0. 81 1 617 .2 16 59.4 2. 8 2. 2 2. 2 2. 68 38 .6 30 .9 36 .0 33 .8 38 .8 34 .3 33 .1 32 . 3 23 .7 10 .8 11 . 53 42. 3 30.6 15 .5 36 .1 34 .3 21 .1 8.5 9.9 38 .9 33 .8 17 .3 32 . 7 31 . 8 22 .8 12 . 6 18 .4 38 .3 ... 18 .4 38 .3 29 .3 14 .1 20 .2 38 .8 24 .7 16 .3 14 .4 37 .8 29 .7 17 .9 22 .1 41. 4 23 .7 12 . 8 12 . 3 35.9 30 .7 21 .0 23 .8 39 .4 24 .1 12 . 7 14 .7 37 .9 28 .9 18 .4 14 .6 9.6 15 .3 60.5 9.7 0.4 2. 3 28 .6 20 .9 14 .7 26 .3 38.0 ... 0 . 23 0. 72 0 .39 Chronic disease at baseline excluded N=6 419 1 RR2 95% CI P trend 1. 00 1 . 21 1. 03 -1. 41 0. 02 1. 00 1 .25 1. 18 1. 06 -1. 47 0.99 -1. 37 1. 00 1 .22 1. 17 1 . 23 1. 03 -1. 44 0.99 -1. 39 1. 02- 1. 48 1. 00...
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Besides increasing the number of universities,rasing the education quality is also urgent problem
... effort to reduce the number of student dropouts Last school year, the number of dropouts was lower than that of the previous school year But for this school year, the measures will be varied from ... have to pay tax, while they will pay 5% in tax in the 6-9 th years, while the full tax of 10 % will be imposed as of the 10 th year of operation MOET will promulgate regulations about the qualifications ... other meetings to disseminate information to their staff, said Quach Tuan Ngoc, head of the Department of Information 11 and Technology under the Ministry of Education and Training The development...
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EFFECT OF THE NUMBER OF THE VERTICAL PIPES FOR THE PASSIVE AERATION ON THE COMPOSTING RATE
... Mixing ratio of the raw materials (-) 60 5.7 5 .1 1 91 455 19 9 12 5 3 51 4 :2: 1 60 6.6 5 .3 18 5 4 41 166 29 3 5 51 3 :2: 1 60 10 .4 5 .2 18 6 4 43 18 1 25 2 39 3 3 :1: 1 Experimental apparatus and procedure The schematic ... composting rate with the number of the perforated pipes for air supply in the bed Fig shows the effect of the number of the pipes on the composting rate, which was determined through Eq (3) It ... clearly found that the number of the vertical pipes greatly affects the composting rate However, the number of the perforated pipes which should be vertically placed in the composting pile should be...
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Tài liệu 67 Detection: Determining the Number of Sources pptx
... Determining the Number of Sources 67 .1 Formulation of the Problem 67 .2 Information Theoretic Approaches AIC and MDL • EDC 67 .3 Decision Theoretic Approaches The Sphericity Test • Multiple Hypothesis ... ASSP 35 , 15 33 15 38 , Nov 19 87 [14 ] Zhao, L.C., Krishnaiah, P. R and Bai, Z.D., On detection of the number of signals in presence of white noise, J Multivariate Analysis, 20 , 1 25 , Oct 19 86 c 19 99 ... sample correlation matrix, which is formed by averaging N samples of the correlation matrix taken from the outputs of the array sensors As R is formed from only a finite number of samples of R, the...
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be the best of whatever you are
... It isn't by size that you win or you fail — Be the best of whatever you are! Nếu đường lớn, Vậy đường mòn nhỏ nhoi Nếu mặt trời tỏa nắng Vậy ánh...
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Đề tài " The number of extensions of a number field with fixed degree and bounded discriminant " docx
... Z/2Z In the former case, the proposition follows from the theorem of Datskovsky and Wright [6] on the number of cubic extensions of number fields (More precisely, EXTENSIONS OF A NUMBER FIELD 737 ... math.GR/05 011 98 [2] M Bhargava, The density of discriminants of quartic rings and fields, Ann of Math 1 62 (20 05), 10 31 10 63 [3] ——— , The density of of discriminants of quintic rings and fields, Ann of ... EXTENSIONS OF A NUMBER FIELD 729 Finally, we need a straightforward fact about points of low height on the complements of hypersurfaces Lemma 2. 4 Let f be a polynomial of degree d in variables x1 ,...
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Đề tài " Growth of the number of simple closed geodesics on hyperbolic surfaces " docx
... have 2s x1 +1 · · · x2sk +1 dx1 · · · dxk k a1 x1 +···+ak xk =T = (2s1 + 1) ! · · · (2sk + 1) ! · T 2| s|+2k 1 2s a1 +2 · · · a2sk +2 · (2| s| + 2k − 1) ! k Now the result follows from Theorem 4 .2, ... independent of the geometry of hyperbolic surfaces Frequencies of different types of simple closed curves From Theorem 1 .2, it follows that the relative frequencies of different types of simple ... depend on g, n and ε Therefore, (3 .14 ) follows from (3 .16 ) and (3 .18 ) Similarly, (3 .15 ) follows from (3 .17 ) and (3 .18 ) Properness and integrability of the function B In this part we show that the...
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24,185 OUTLETS - The number of JApAN pOST BANk outlets in Japan docx
... 4,5 32 Chugoku 11 44 1, 154 1, 154 13 3, 435 3, 088 Kanto 4,995 6,9 81 2, 235 2, 16 7 11 1 Kinki 3, 411 4,065 Shikoku Kyushu 20 1 24 9 Okinawa 24 ,18 5 635 JAPAN POST BANK Average of Japan’s Mega Banks 1, 750 Number ... pension Others 1 ,20 0 800 400 20 01 20 02 20 03 Source: Bank of Japan “Flow of Funds” 12 Japan post Bank Annual Report 20 10 20 04 20 05 20 06 20 07 20 08 20 09 20 10 FISCAL YEAR the Distinctive Role of ... this extensive network, JApAN pOST BANk has an extremely close and convenient presence for people living in all regions of Japan, and as a result the Bank has become an integral part of their daily lives Japan 10 Tohoku 23 4 Branches 23 ,9 51 Post Offices 26 ,19 1 ATMs 2, 5 72 2 ,27 8 (As of March 31 , 20 10 ) Chubu 33 ...
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Cancer Research UK’s strategy 2009–2014: Cancer Research UK’s aim is to reduce the number of deaths from cancer. Our future plans are ambitious, but they are in line with the challenge and the responsibility we face. docx
... Registered charity number 10 89464 Registered company number 4 32 5 234 Copyright © 20 08 Cancer Research UK LF 1 13 Over the next five years we will see further dramatic progress in the prevention, diagnosis ... - Expand public engagement and information provision - Be the first port of call for new developments and strategic initiatives - Offer an opportunity to develop new partnerships, for example ... 30 20 Myeloma Stomach Brain Lung Pancreas 10 19 71- 72 Year 19 80- 81 1990- 91 20 00- 02 *15 -99 years **Coleman M (20 07) 20 20 goals launch Causes and prevention Our researchers have been at the forefront...
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Đề tài "Stretched exponential estimates on growth of the number of periodic points for prevalent diffeomorphisms I " potx
... to the strategy of the proof of Theorem 1. 3. 9 At the n-th stage of the induction over the period we consider the family of polynomial ˜ perturbations {f
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báo cáo sinh học:" Doubling the number of health graduates in Zambia: estimating feasibility and costs" pdf
... 15 4 15 01 7 824 93 61 634 4 34 788 24 7 Library Build new libraries Refurbish or expand existing libraries 10 5 6 12 23 23 95 37 21 4 10 5 1 82 16 1 63 726 4 72 16 11 24 5 18 57 419 4 30 86 746 27 0 13 8 57 Buy new ... Build new staff offices 710 12 9 2 31 0 19 32 475 4 633 19 7 Laboratories Build new skills laboratories 11 8 12 0 84 29 35 0 Update current skills laboratories and equipment 16 0 425 31 64 6 81 Build new ... institution output 20 07 Output 20 12 Output, Post Scale-up Medical doctor 67 15 0 Nurse 900 1, 636 Midwife 30 0 765 Medical licentiate 20 20 Clinical officer 13 3 19 0 Post basic nurse (teaching staff) 35 50...
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báo cáo hóa học:" The integrated care pathway reduced the number of hospital days by half: a prospective comparative study of patients with acute hip fracture" doc
... purposes) Journal of Orthopaedic Surgery and Research 20 06, 1: 3 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 http://www.josr-online.com/content /1/ 1 /3 Zander K: Historical development of outcomes-based ... Range (3 10 ) (3 10 ) Intra-capsular fracture 29 21 Hemiartroplasty 28 18 80 – 10 0 % 36 35 Osteosynthesis with 60 – 79 % 13 10 < 60 % 11 Mean 84 82 SD (16 .5) ( 23 .1) 0 .1 Two parallel nails Extra capsular ... (7.0) Comparison N = 56 12 12 Living With someone 19 14 Alone 37 42 Need of home help services 0.4 34 28 Daily Place of accident None Once a week 15 19 27 22 Type of walking aid At home 41 43 Outside...
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báo cáo hóa học:" Prevalence of visual impairment in relation to the number of ophthalmologists in a given area: a nationwide approach" ppt
... CL 1. 00 1. 51 na 1. 12 2. 03 1. 00 0. 91 na 0 .33 2. 51 2. 10 1. 08 0.96 0.97 1. 11 1 .34 1. 34 3 .28 0.79 1. 47 0. 71 1. 32 0.77 1 . 21 0.66 1. 86 0. 81 2. 20 1. 40 3. 60 0. 91 1 .38 0 .28 1. 05 0 .29 –6. 71 0. 42 31 . 09 0 .27 3. 03 ... 0 .10 –58.00 0 .11 –7 .15 0 . 13 – 12 . 01 0 .22 –8.55 0.09–88 .38 0 .11 – 43. 46 0 .24 –7. 52 0 .20 16 .67 0 .16 11 .11 0 .10 –7.45 0 .24 11 .38 0 . 23 –5.75 0 .19 10 .34 0 .19 3 .10 0 . 21 10 .37 0. 03 4 42. 19 0 . 23 3 .22 0.08–59 .30 0 .15 2. 77 ... 0.85 2. 26 1. 04–4 . 23 0 .34 –0. 73 0.70 2. 07 0 .27 –0. 81 0. 52 1. 06 0 .36 1. 04 0.47 1 .20 0.54 1. 12 2 .38 0.90 1 .27 1. 36 2. 79 2. 17 1. 34 1. 82 1. 35 0.87 1. 65 1. 16 1. 39 0.76 1. 47 3. 88 0.87 2. 24 0.64 0.64 Na 0 .10 –58.00...
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Báo cáo hóa học: "ON THE SYSTEM OF RATIONAL DIFFERENCE EQUATIONS xn+1 = f (xn , yn−k ), yn+1 = f (yn ,xn−k )" potx
... M = f M1 ,Pk +1 ≤ f M1 ,g(M) ≤ f M,g(M) , (2. 11 ) from which it follows that M1 = M, Pk +1 = g(M) (2. 12 ) In a similar fashion, we may obtain that f M,g(M) = M = M1 = f M2 ,Pk +2 ≤ f M2 ,g(M) ≤ f M,g(M) ... Every positive solution of (1 .2) converges to a positive equilibrium (x, y) of (1 .2) satisfying (1. 3) as n → ∞ Proof of Theorem 1. 1 In this section we will prove Theorem 1. 1 To this we need the following ... − ε), if j ∈ {k + 1, ,2k + 1} (2. 17 ) From (1 .2) and (2. 17 ), we have yls −k = f yls −k 1 ,xls −2k 1 < f g(M − ε),M − ε = g(M − ε) (2. 18 ) Also (1 .2) , (2. 17 ) and (2. 18 ) implies xls +1 = f xls ,...
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Báo cáo hóa học: " REDUCING THE NUMBER OF FIXED POINTS OF SOME HOMEOMORPHISMS ON NONPRIME 3-MANIFOLDS" ppt
... 2 = g 32 g 12 g 33 , and 3 = g 31 g 22 g 33 g 23 (see Figure 4.4) The numbers of |αi ∩ S j |’s in two cases are listed as follows: S1 S2 S3 1 2 3 — 2 — — S1 S2 S3 1 2 3 — 2 — 2 — 16 Fixed points ... points of slide homeomorphisms T3 T3 2 2 S1 S1 3 T1 S3 T2 S3 S2 1 3 T1 T2 S2 1 Figure 4.4 Thus, the sum in Proposition 4.6 is 3 ∩ S1 1 ∩ S2 2 ∩ S3 + 1 ∩ S3 2 ∩ S1 + 2 ∩ S1 1 ∩ S2 + 1 ... ∩ S2 2 ∩ S1 + 3 ∩ S1 1 ∩ S3 + 1 ∩ S3 3 ∩ S1 + 3 ∩ S2 2 ∩ S3 + 2 ∩ S3 3 ∩ S2 3 ∩ S2 (4. 12 ) In the case shown on the left, it is (8 + 0) + (4 + 4) + (0 + 0) + (8 + 8) = 32 ; in the other...
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Tìm thêm: hệ việt nam nhật bản và sức hấp dẫn của tiếng nhật tại việt nam xác định các nguyên tắc biên soạn khảo sát các chuẩn giảng dạy tiếng nhật từ góc độ lí thuyết và thực tiễn khảo sát chương trình đào tạo của các đơn vị đào tạo tại nhật bản khảo sát chương trình đào tạo gắn với các giáo trình cụ thể tiến hành xây dựng chương trình đào tạo dành cho đối tượng không chuyên ngữ tại việt nam điều tra đối với đối tượng giảng viên và đối tượng quản lí điều tra với đối tượng sinh viên học tiếng nhật không chuyên ngữ1 khảo sát thực tế giảng dạy tiếng nhật không chuyên ngữ tại việt nam khảo sát các chương trình đào tạo theo những bộ giáo trình tiêu biểu mở máy động cơ rôto dây quấn hệ số công suất cosp fi p2 đặc tuyến mômen quay m fi p2 đặc tuyến tốc độ rôto n fi p2 sự cần thiết phải đầu tư xây dựng nhà máy thông tin liên lạc và các dịch vụ phần 3 giới thiệu nguyên liệu từ bảng 3 1 ta thấy ngoài hai thành phần chủ yếu và chiếm tỷ lệ cao nhất là tinh bột và cacbonhydrat trong hạt gạo tẻ còn chứa đường cellulose hemicellulose chỉ tiêu chất lượng theo chất lượng phẩm chất sản phẩm khô từ gạo của bộ y tế năm 2008 chỉ tiêu chất lượng 9 tr 25