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PERFECTIONNEMENT DE COMMUNICATIONS SECURISEES AGT EN UTILISANT LA CRYPTOGRAPHIE QUANTIQUE
Ngày tải lên :
27/10/2016, 23:16
... volume 74, pages 14 519 5, Janvier 2002 [9] P M Gorman, P R Tapster, and J G Rarity "Secure FreeSpace Key Exchange To 1. 9 km In J Mod Opt of Physics, volume 48, pages 18 8 719 01, 20 01 [10 ] Guihua Zeng ... et Scộnarios 2 .1 2 .1. 1 2 .1. 2 2 .1. 3 Scộnario dộchange de clộ quantique Station transmet la clộ au satellite Satellite transmet la clộ la station 11 Station transmet la clộ ... satellite : 10 cm, et le poids de tộlescope : kg Deux types de tộlescope sur la terre Tộlescope au sol 50 cm 10 0 cm Dộpistant et pointage au sol > 10 0 àR > 10 0 àR Stabilitộ de pointage du 12 àR 12 àR...
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Bài giảng Chapter 7 The Quantum-Mechanical Model of the Atom
Ngày tải lên :
28/11/2013, 01:11
... frequency of 10 0.7 MHz Given: ν = 10 0.7 MHz Find: λ, (m) Concept Plan: ν (ΜHz) -1 10 s MHz ν (s -1) c λ= ν λ (m) Relationships: λ∙ν = c, MHz = 10 6 s -1 Solve: 10 6 s -1 100.7 MHz × = 1. 007 10 8 s -1 MHz ... photon Tro, Chemistry: A Molecular Approach h = 1. 0 10 J 8.5 10 27 = 1. 176 10 −26 J (1. 176 10 ) −26 J 6.626 × 10 −34 J • s = 1. 8 × 10 7 s -1 34 Ejected Electrons • photon at the threshold ... Plan: ν (s -1) λ (m) c λ= ν nm λ (nm) 10 −9 m Relationships: λ∙ν = c, nm = 10 -9 m Solve: c 3.00 10 8 m • s -1 λ= = = 6.49 10 −7 m ν 4.62 10 14 s -1 nm −7 6.49 10 m × −9 = 6.49 10 nm 10 m Check:...
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Tài liệu THE QUANTUM IN CHEMISTRY: An Experimentalist’s View pptx
Ngày tải lên :
15/02/2014, 17:20
... Solution 8 .13 4 J K 1 mol 1 (273 .15 K) P 0.022 414 m3 mol 1 − 0.00003 91 m3 mol 1 1. 012 2 × 10 5 Pa − 0 .14 08 Pa m3 mol 1 0.022 414 m3 mol 1 0.9990 atm For the ideal gas P RT Vm 8 .13 4 J K 1 mol 1 (273 .15 K) ... Solids 11 79 11 53 11 71 xiii Contents 28.5 The Structure of Liquids 11 84 28.6 Approximate Theories of Transport Processes in Liquids 11 88 28.7 Polymer Conformation 11 94 28.8 Polymers in Solution 11 98 ... 20 .17 9 g 0.9 911 mol V (22.400 L) m3 10 00 L 0.022400 m3 We now carry out the numerical calculation: P nRT V (0.9 911 mol) 8. 314 J K 1 mol 1 (273 .15 K) 0.022400 m3 1. 005 × 10 5 J m−3 1. 005 × 10 5...
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Tài liệu Đề tài " Asymptotic faithfulness of the quantum SU(n) representations of the mapping class groups " pdf
Ngày tải lên :
16/02/2014, 05:20
... − 1) 2 2k But by (17 ) we get that (k) (k) Pσ0 , 1 T(fr )0 ,σ0 − T(fr )1 , 1 = Θk (1) ≤ C1 nk (1) 1/2 The theorem then follows from these two estimates, since (fr )0 = f and T(fr )1 , 1 − Tf, 1 ... π)k −i−j 2k i=0 j=0 l=0 √ r r r 1 + ( 1) j nj πcl (f G , hi )πk −l−i−j +1 2k i=0 j=0 l =1 √ r r r 1 − ( 1) j nj πcl (fG , hi )πk −l−i−j +1 = O(k −r 1 ) 2k − i=0 j=0 l =1 Note that the expression inside ... Vol 19 89/90, e [AB] M Atiyah and R Bott, The Yang-Mills equations over Riemann surfaces, Philos Ast´risque No 18 9 -19 0 (19 90), Exp No 715 , 7 16 e Trans Royal Soc London A308 (19 82), 523– 615 [ADW]...
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The Quantum-Mechanical Model of the Atom pdf
Ngày tải lên :
09/03/2014, 00:20
... (Hz) 10 10 10 10 12 10 14 Visible light Microwave Infrared Radio Low energy 10 10 10 16 10 18 Ultraviolet 10 20 X-ray 10 22 10 24 Gamma ray AM TV FM Cell Wavelength, λ (m) 10 750 Red 10 10 700 10 ... = -2 .18 * 10 -18 J (1> n2) E = hc>l SOLVE Follow the conceptual plan Begin by calculating ⌬Eatom SOLUTION ⌬Eatom = E - E = -2 .18 * 10 -18 J a 1 b - c -2 .18 * 10 -18 J a b d = -2 .18 * 10 -18 J a 1 - ... spacing between the energy levels becomes smaller E4 = 1. 36 × 10 19 J E3 = –2.42 × 10 19 J n=2 E2 = –5.45 × 10 19 J n =1 E1 = –2 .18 × 10 18 J Energy n=4 n=3 The Angular Momentum Quantum Number...
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Báo cáo "Quantum kinetic equation in the quantum hadrondynamics (QHD-I) model " pptx
Ngày tải lên :
22/03/2014, 11:20
... ) as follows 1/ 2 1/ 2 Ψ =Zψ Ψr , Φ = Zφ Φr , 1/ 2 ¯ ¯ Ψ =Zψ Ψr , 1/ 2 µ µ (Wµ, ω µ ) = Zω (Wr , ωr ), (6) P.H Lien / VNU Journal of Science, Mathematics - Physics 24 (2008) 14 5 -15 4 14 7 the external ... external sources 1/ 2 ηr , Jφ = Zφ 1/ 2 ηr , ¯ 1/ 2 µ Lµ = Zω Jr , η =Zψ η =Zψ ¯ 1/ 2 Jr , (7) the coupling constants 1/ 2 gr =gZφ Zψ /Zg , r 1/ 2 gω = gω Zgω , λ2 =λ2 Zφ /Zλ , r cr = cZφ , 1/ 2 (8) and ... (14 ) 14 8 P.H Lien / VNU Journal of Science, Mathematics - Physics 24 (2008) 14 5 -15 4 where g, gω and λ are the renormalized Yukawa couplings, and the terms δψ = Zψ − 1, δφ = Zφ − 1, δω = Zω − 1, ...
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Đề tài " On the distribution of matrix elements for the quantum cat map " pptx
Ngày tải lên :
29/03/2014, 07:20
... D(m)D(n) N = D12 (m)D 21 (n) + D 21 (m)D12 (n) + Dii (m)Dii (n) i =1 where D12 (m), D 21 (m), D12 (n) and D 21 (n) are all O(N 1/ 2 ) Thus N TN (m)ψi , ψi TN (n)ψi , ψi = tr D(m)D(n)∗ + O(N 1 ) i =1 The proof ... (see (2 .1) ), valid for odd N and B1 , B2 ∈ C(2N ): tr(TN (nB1 )TN (mB2 )∗ ) = ( 1) m1 m2 +n1 n2 N if nB1 ≡ mB2 otherwise mod N , We get (4 .1) N N Vν (ψj )Vµ (ψj ) j =1 = = ( 1) m1 m2 +n1 n2 |C(2N ... say C1 or C2 But 1 µ2 = C1 implies C that 1 = µ2 N1 and hence µ4 = µ3 C1 +K We thus obtain N3 µ2 − C1 N2 = 1 − µ2 = µ4 − µ3 = µ3 − C1 + K N3 C Now, if 1 = µ2 then both − N1 and − C1 +K...
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the quantum physics of black holes and string theory
Ngày tải lên :
18/04/2014, 15:30
... S Commun Math Phys 43 :19 9 (19 75) Hawking S Phys Rev D 13 :19 1 (19 76) Hawking S Phys Rev D 14 :2460 (19 76) Giddings SB hep-th/950 815 1 (19 95) Zurek WH Phys Rev Lett 49 :16 83 (19 82) Banks T, Peskin ... Phys B244 :13 5 (19 84) 10 Unruh WG, Wald RM Phys Rev D 52: 217 6 (19 95) 11 ’t Hooft G Nucl Phys B256:727 (19 85) 12 Keski-Vakkuri E, Lifschytz G, Mathur SD, Ortiz M Phys Rev D 51: 1764 (19 95) 13 Keski-Vakkuri ... 75:4724 (19 95) 19 Polchinski J hep-th/9 611 050 (19 96) 20 Sen A hep-th/9904027 (19 99) 21 Witten E Nucl Phys B460:335 (19 96) 22 Tseytlin A hep-th/990 810 5 (19 99) 23 Montonen C, Olive D Phys Lett B72 :11 7...
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scientific american - 1993 04 - controlling the quantum jitters of atoms
Ngày tải lên :
12/05/2014, 14:49
... AMERICAN, 415 Madison Avenue, New York, N.Y 10 017 -11 11, or fax ( 212 ) 754 -11 38 Subscription correspondence should be addressed to Subscription Manager, SCIENTIFIC AMERICAN, P.O Box 318 7, Harlan, IA 515 37 ... and Technology (right) 10 6 10 7 Neil McDonald 11 0 Maunsell Structural Plastics (top and bottom) 11 1 John James Danehy 12 0 12 1 Andrew Christie 69 Jana Brenning 70 Jason KŸÝer 71 72 Jana Brenning 73 ... economicÑof an aging population 3,000 19 90 2,500 2,000 1, 500 19 00 1, 000 500 50 55 60 65 70 SOURCE: Social Security Administration 75 80 85 90 AGE (YEARS) 95 10 0 10 5 11 0 11 5 12 0 PATTERNS OF DEATH AND DISABILITY...
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squires, the mystery of the quantum world (second edition)
Ngày tải lên :
05/06/2014, 11:21
... as defined in 1. 1, is not a property of our world; probability enters physics in an intrinsic way and not just through our ignorance The situation is The breakdown of determinism 11 thus different ... will find R+T=N (1 2) Provided N is large, the probability of transmission is defined to be T divided by N and the probability of reflection R divided by N, i.e (1. 3) and (1. 4) 12 Reality in the ... accuracy such that U,is equal to one hundredth of a centimetre (10 -4m) Then, according to equation (2 .1) , the error in velocity will be about 10 -”m per year Thus we see that the uncertainty principle...
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Báo cáo hóa học: " Effects of Shape and Strain Distribution of Quantum Dots on Optical Transition in the Quantum Dot Infrared " doc
Ngày tải lên :
22/06/2014, 01:20
... -0 .13 (blue) to 0 .12 (red) 12 -0.07500 (a) 12 8 4 0 εH -4 -8 -12 -12 -12 12 εB -4 -8 Z Axis (nm) -0 .13 00 (b) -8 -4 12 -12 12 (c) 8 12 12 (d) -4 -8 εH -4 εB -4 -8 -8 0.07000 -12 -12 -8 -4 12 0 .12 00 ... included 1. 8 pyramid QD 1. 8 1. 6 1. 4 1. 4633 eV 1. 3425 eV Energy (EV) 0.8 0.6 1. 2903 eV 1. 2 1. 0 0.8 0.8 0.6 CB HH LH 1. 2 1. 0 1. 0884 eV 0.6 0.4 0.0978 eV 0.2 0.0 -0.2 -30 -20 -10 10 20 1. 1339 eV ... Ref [17 ] The investigated three different shaped InAs QDs follows pyramid-shaped (with the four facets being (11 1), ð" 11 1Þ; 1" and ð"" 11 Þ; 11 1ÞÞ InAs QD with the height and base ˚ being 81 and...
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The Quantum Mechanics Solver 28 docx
Ngày tải lên :
02/07/2014, 07:20
... J.-M., 11 9, 14 5 Raizen, M., 285 Ramsey, N.F., 47, 53, 15 6 Reichel, J., 285 Rich, J., VII Richard, J.-M., 19 2 Roger, G., 10 8 Rosen, N., 99, 10 8 Roug´, A., VII e Maali, A., 11 9, 14 5 Maitre, X., 11 9 ... 63, 15 9 meson, 17 , 18 7 modes, 267 molecular ions, 2 31 muon, 17 factorized spin, 10 0 Fermi golden rule, 11 fermion, 10 field quantization, 13 1 fine structure constant, 32 flavor, 20 form factor, 13 ... measurement, 15 3, 16 7 quantum boxes, 215 quantum cryptography, 12 1, 12 5 quantum dots, 215 quantum eraser, 15 5, 15 9 quantum measurement, quantum paths, 15 5, 16 2 quantum reflection, 255 quantum revival, 13 7...
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The Quantum Mechanics Solver 1 ppsx
Ngày tải lên :
02/07/2014, 07:20
... State 11 1 o 12 .3 Quantum Superposition Versus Statistical Mixture 11 1 12 .4 The Fragility of a Quantum Superposition 11 2 12 .5 Solutions ... 10 0 11 .4 A Simple Hidden Variable Model 10 1 11 .5 Bell’s Theorem and Experimental Results 10 2 11 .6 Solutions ... 11 4 12 .6 Comments 11 9 13 Quantum Cryptography 12 1 13 .1 Preliminaries ...
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The Quantum Mechanics Solver 2 docx
Ngày tải lên :
02/07/2014, 07:20
... values j1 and j2 (of dimension (2j1 + 1) × (2j2 + 1) ), the possible values for the quantum number j corresponding ˆ to the total angular momentum of the system J are: j = |j1 − j2 | , |j1 − j2 ... states j = 1, m = 0, 1) The relation between the factorized basis |j1 , m1 ⊗ |j2 , m2 and the total angular momentum basis |j1 , j2 ; j, m is given by the Clebsch-Gordan coefficients: |j1 , j2 ; ... restriction of ˆ ˆ λH1 to the subspace of H0 associated with the eigenvalue En , i.e find the pn solutions of the “secular” equation: ˆ ˆ n, 1| λH1 |n, − ∆E n, 1| λH1 |n, pn ˆ n, r|λH1 |n, r − ∆E...
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The Quantum Mechanics Solver 3 docx
Ngày tải lên :
02/07/2014, 07:20
... Neutrino Oscillations Ndetected N expected 1, 2 1, 0 0,8 0,6 ILL Bugey Rovno Goesgen Chooz KamLAND 0,4 0,2 10 10 2 distance (meters) 10 3 10 4 10 5 Fig 1. 1 Ratio between the numbers of observed electron ... to the reactor |∆m2 | c4 = 7 .1 (± 0.4) × 10 −5 eV2 , tan2 θ = 0.45 (± 0.02) (1. 7) Show that these values are consistent with the result Pe = 0. 61 (± 0 .10 ) of Fig 1. 1 1. 2 Oscillations of Three Species; ... ( i Uβi Uαi = δαβ ) and it can be written as: ⎞ ⎞⎛ ⎞⎛ ⎛ s13 e−iδ c13 c12 s12 0 ˆ ⎠ ⎝ −s12 c12 ⎠ U = ⎝ c23 s23 ⎠ ⎝ iδ −s23 c23 0 −s13 e c13 where cij = cos θij and sij = sin θij The complete experimental...
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