... many processors can manipulate the data in the nodes of the data structure in parallel. Each processor in the CM can have its own local variables. These variables are called parallel variables, ... implementing parallel nat- ural language programs on real hardware has clarified which operations and programming techniques are the most efficient and useful. Programs that build upon general algorithms ... or parallel fields. When a host computer program per- forms a serial operation on aparallel variable, that op- eration is performed separately in each processor in the CM. For example, a...
... MCG data and angiographic data. Fi-nally, microvascular disease, not associated with de-finable epicardial vessel lesions on angiography, re-sulting in myocardial ischemia can create a false ... that each patient was already scheduled for the reference coronary an-giography for any indication. Coronary angiographic data was recorded digitally and on cine angiographic film and was ... central server location in New York. All MCG analyses in this da-tabase have been validated against the final medical and angiographic diagnoses, confirmed by two inde-pendent academic angiographers...
... ffPotentiallyparallelizablepart…fT (1 – f)T/nFigure 8-9. (a) A program has a sequential part and a parallel- izable part. (b) Effect of running part of the program in paral-lel.CPU CPU CPUPacketgoing ... multiprocessor. (a) Machine 1 Machine 2Languagerun-timesystemOperatingsystemShared memoryApplicationHardwareLanguagerun-timesystemOperatingsystemApplicationHardware(b)Machine 1 Machine 2Languagerun-timesystemOperatingsystemShared ... 2Languagerun-timesystemOperatingsystemShared memoryApplicationHardwareLanguagerun-timesystemOperatingsystemApplicationHardware(c)Machine 1 Machine 2Languagerun-timesystemOperatingsystemShared...
... 230V AC isstill present.AC WaveformsWhile a DC voltage doesn’t change, AC voltage is always alternatingback and forth in a fixed way. The voltage is constantly changing fromsome positive value, ... Faraday’s armature was a stationary coil ofwire, though generators may make use of moving or rotating wire coils.Next, we’ll look at a simple way of using a permanent magnet field alongwith a ... manufacturers and sellers to distinguish their prod-ucts are claimed as trademarks. Where those designations appear in this book, and ThePragmatic Programmers, LL C was aware of a tra demark claim,...
... sub-sentential alignmentsin parallel corpora and applied it on three differ-ent parallel corpora that are part of the same auto-motive corpus. Comparisons with standard termi-nology extraction programs ... conditioningcommande controltableau panel2. combine each NP + PP chunk:commande de climatisa-tion automatiqueautomatic air condition-ing controltableau de commande declimatisation automatiqueautomatic ... of the candidate terms.The candidate terms are generated in severalsteps, as illustrated below for example (3).(3) Fr: Tableau de commande de climatisation automa-tiqueEn: Automatic air conditioning...
... onto a massively parallel SIMD (MP-SIMD) chip, amassivelyparallel processor array (MPPA) and onto an field-programmable gatearrays (FPGA).1 IntroductionNowadays, medical experts have to deal ... the task parallelism instead ofits massive data parallelism also provides good results.3 Pixel -Parallel Processor ArraysConventi onal image-processing systems (which integrate a camera and a ... done on-chip and that a parallelismdegree as high as in the pixel -parallel processor arraycannot be achieved due to the shortage of hardwareresources, an alternative architecture was proposedNieto...
... temp;}OUTPUTEnter the RangeLower limit a = 0Upper limit b = 6Enter the number of subintervals = 6Value of the integral is: 1.3571598 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUESEnter the value of ... ALGORITHM FOR TRAPEZOIDAL RULEStep 1. Start of the program for numerical integrationStep 2. Input the upper and lower limits a and bStep 3. Obtain the number of subinterval by h = (b a) /nStep 4. ... initial and final limits =:”); COMPUTER PROGRAMMING IN ‘C’ LANGUAGE603 13.34ALGORITHM FOR FITTING A STRAIGHT LINE OF THE FORMY = a + bXStep 1. Start of the program for fitting straight lineStep...
... This pageintentionally leftblankThis pageintentionally leftblank A TEXTBOOK OF COMPUTER BASED NUMERICALANDSTATISTICAL TECHNIQUESAnju Khandelwal M.Sc., Ph.D.Department of MathematicsSRMS ... Based Numerical and Statistical Techniques’ is primarily writtenaccording to the unified syllabus of Mathematics for B. Tech. II year and M.C .A. I year studentsof all Engineering colleges affiliated ... program in C-language to understand the steps and methodology used in writing the program.Thorough care has been taken to eradicate errors but perfection cannot be claimed. Thereader are requested...
... problems. A majoradvantage for numerical technique is that a numerical answer can be obtained even when a problem has no analytical solution. However, result from numerical analysis is an approximation,in ... value – Approximate value A computer has a finite word length and so only a fixed number of digits are stored andused during computation. This would mean that even in storing an exact decimal ... converted to decimal form understandable to the users and some more error maybe introduced at this stage. In general, we can say that Error = True value – Approximate value. Theerrors may be divided...
... approximately equal to the algebraicsum of their relative errors.Example 23. The discharge Q over a notch for head H is calculated by the formulaQ = kH5/2, where k is a given constant. If ... 3Hence maximum percentage error (Ep)max = 11.667%.Example 26. How accurately should the length and time of vibration of a pendulum should bemeasured in order that the computed value of ... ERRORS AND FLOATING POINT9Example 11. Find the relative error in calculation of 7.3420.241. Where numbers 7.342 and 0.241 arecorrect to three decimal places. Determine the smallest interval...
... Given δb = 2 mm = 0.2 cm a = 1 mm = 0.1 cmsin A = −⇒=1sin a a A bb∂∂ A a= 222211 11babab⋅=−−∂∂ A b= 2222211aababbab⋅− =−−− A < AAabaa∂∂δ+δ∂∂22 2212.30.1 ... 32. In a ∆ABC, b = 9.5 cm, c = 8.5 cm and A = 45o, find allowable errors in b, c, and A such that the area of ∆ABC may be determined nearest to a square centimeter.Sol. Let area of the ∆ABC be ... semantics are also specified in detail by the IEEE standards, are notalways handled the same way. It turns out that many manufacturers believe (sometimes rightlyand sometimes wrongly) that...
... obtained byx1= 22244and22bb ac bb acaa−+ − −− −=xThese are called closed form solution. Similar formulae are also available for cubic andbiquadratic polynomial equations but we rarely ... 0.1823e3]CHAPTER 2Algebraic and Transcendental Equation2.1 INTRODUCTIONWe have seen that expression of the formf(x)= a 0xn + a 1xn –1 + + a n –1x + a nwhere a s are constant (a 0≠ 0) and ... 26 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUESThe basic operations specified by IEEE arithmetic are first and foremost addition, subtraction,multiplication, and division. Square roots...
... negative.Thus f(0.5) is negative and f(1) is positive. Then the root lies between 0.5 and 1.40 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUESSecond approximation: The second approximation ... f(0) is negative and f(1) is positive, therefore, a root lies between 0 and 1.ALGEBRAIC AND TRANSCENDENTAL EQUATION37Here ei and ei + 1 are the errors in ith and (i + 1)th iterations respectively. ... of the Equation f(x) = 0Step 1: Choose two initial guess values (approximation) a and b (where (a > b)) such thatf (a) . f(b) < 0.Step 2: Evaluate the mid point x1 of a and b given...
... 1.40360.10203=Since, x3 and x4 are approximately the same upto four places of decimal, hence the requiredroot of the given equation is 1.4036.48 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUESUsing ... four places of decimal.ALGEBRAIC AND TRANSCENDENTAL EQUATION53Example 3. Using the method of False Position, find the root of equation x6 – x4 – x3 –1 = 0 upto four decimal places.Sol. ... between 1.6866 and 2.50 COMPUTER BASED NUMERICAL AND STATISTICAL TECHNIQUESand f(3) = (3)3 – 2(3) – 5 = 16Therefore, a root lies between 2 and 3.First approximation: Therefore taking x0 =...