C 34 04 bai toan ve phan ung dot chay axit cacboxylic

7 385 0
C 34 04 bai toan ve phan ung dot chay axit cacboxylic

Đang tải... (xem toàn văn)

Thông tin tài liệu

www.tuhoc.edu.vn • nCO2 nH2O • nCO2 nH O naxit – – VD1: V lít O2 nCO C1: nH O 0,2 mol H2O Tính V naxit nH2n–2O2 nH2n–2O2 nO nH O 3n O2 + 3n n to nO2 nCO2 + (n–1)H2O n H2O 0,3 (mol) V 6, 72 (lÝt) C2: 2na xit 0,1 2nO 2nCO 2 0,3 nH O nO 0,3 (mol) V 6, 72 (lÝt) 0,2 TOPPER Chú ý nhánh) 4,032 lít CO2 X A) HOOC–(CH2)4–COOH C) HCOOH B) CH3COOH D) HOOC–COOH htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn 2 0,2 mol H2 A) HCOOH C2H5COOH B) CH2=CH–COOH CH2=C(CH3)–COOH C) CH3COOH C2H5COOH D) CH3COOH CH2=CH–COOH A) HOOC–(CH2)3–COOH C) HOOC–(CH2)2–COOH 0,2 mol H2 B) HOOC–CH2–COOH D) HOOC–(CH2)4–COOH A A) CH2O2 C) C3H4O2 < MB B) C2H4O2 D) C2H2O4 gam CO2 19,8 gam H2 A) C2H5OH C) C3H8O2 B) C3H8O3 D) C2H6O2 Y 33,6 lít khí CO2 H2SO4 A) 18,24 C) 22,80 > nX B) 34,20 D) 27,36 htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn • R(COOH)a + aNaOH NCOOH a R(COONa)a + aH2O nNaOH naxit • R(COOH)a + aNaHCO3 NCOOH a R(COONa)a + aH2O + aCO2 nCO2 naxit A) HOOC–CH2CH2–COOH C) CH3COOH B) C2H5COOH D) HOOC–COOH 2 A) axit axetic C) axit oxalic B) axit malonic D) axit fomic CO2 A) HCOOH, HOOC–COOH B) HCOOH, HOOC–CH2–COOH C) HCOOH, C2H5COOH D) HCOOH, CH3COOH htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn A z mol H2O (z = y – y mol CO2 E A) axit oxalic C) B) axit acrylic D) axit fomic B c mol H2 3, thu A) CH2=CH–COOH C) HOOC–COOH B) HOOC–(CH2)3–COOH D) HCOOH C mol H2 0,2 A) CH3COOH HOOC–CH2–COOH B) HCOOH HOOC–COOH C) HCOOH HOOC–(CH2)4–COOH D) CH3COOH HOOC–COOH D 2 CO2 y mol H2 A) 0,2 B) 0,3 C) 0,6 D) 0,8 E CO2 a gam H2 B) 1,44 C) 3,60 A) 1,62 D) 1,80 F Y < MZ) mol CO2 A) 46,67 % C) 25,41 % B) 40,00 % D) 74,59 % htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn VD2: 2 RCOOH + Na RCOONa + ½H2 R'(COOH)2 + Na R'(COONa)2 + H2 n R COOH nH2 x y 0, x x x nR '(COOH)2 y 0, 0, nCO2 naxit 0, x y NC x y 0,3 x y 0, 2 0, 0, 0,3 (mol) x y 0, 0,1 mCH3COOH 0, 60 12 (gam) m(COOH)2 0,1 90 (gam) 12 0, x y NC = (do NC 3COOH (Y) HOOC–COOH (Z) 0, NC htttp://tuhoc.edu.vn/blog y 1,5 < NC < %Z 0, (mol) 0,2 < x + y < 0, NC Thay vào y 100% 42, 86 % www.tuhoc.edu.vn G 2 A) C2H4O2 C3H4O2 C) C2H4O2 C4H6O4 B) CH2O2 C4H6O2 D) CH2O2 C3H4O2 H 2 A) HCOOH (COOH)2 B) CH3COOH HOOC–(CH2)2–COOH C) CH3CH2COOH (COOH)2 D) CH3COOH HOOC–CH2–COOH I 2 A) 72,22 % C) 35,25 % B) 27,78 % D) 65,15 % J gam N2 A) 46,39 % C) 65,15 % B) 35,25 % D) 55,25 % htttp://tuhoc.edu.vn/blog www.tuhoc.edu.vn Câu Câu A B B D C A B D C B E B C F C A G A D H D D I B A J D A A htttp://tuhoc.edu.vn/blog

Ngày đăng: 15/10/2016, 10:54

Từ khóa liên quan

Tài liệu cùng người dùng

Tài liệu liên quan