Vật lý 12 tóm tắt lý thuyết và bài tập trắc nghiệm tập 1 (p4)

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Vật lý 12 tóm tắt lý thuyết và bài tập trắc nghiệm tập 1 (p4)

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H THUYgt HmitU Cau 68: (De thi dai hpc nam 2007) D5t hieu di?n the u = Uosincot (Uo khong doi) vao hai dhu doan mach RLC khong phan nhanh BiSt dien tro thuin cua mach khong d6i Khi c6 hien tucmg cong huong dien doan mach, phat bieu nao sau day sal? A Hieu dien the hi?u d\ing a hai dau difn tra R nho hon hieu dien thk hi?u dung a hai diu doan mach B Cuomg hi?u dvmg cua dong dien mach dat gia tri Ion nhat C Hieu dien the tiic thai a hai dau doan mach cung pha vdi hieu dien thg tiic thai a hai dhu dien tra R D Cam khang va dung khang cua doan mach bing Cau 69: Mach dien khong phan nhanh g6m dien tra thuin R = lOOQ, cuon day thuan cam c6 dp t\ cam L = - H v a tu di§n c6 di?n dung C thay doi dugc Mac mach dien vao ngu6n (220V-50Hz) D6 cucmg hi?u d\mg qua mach CO gia tri cue dai thi gia tri cua C la CHlfflHBSlDdHSnigHllBAYCmgO VAl B.1«1F 12 - T J M T A T LY V A BAI T ^ P T R A C C.H21F D.^^J " n n n Cau 70: Trong doan mach RLC n6i tiep dang xay cpng huong di$n Tang dkn tan s6 dong dien va giO nguyen cac thong s6 cua mach, ket luan nao sau day la dung A He so cong suat cua doan mach giam B Cucmg hi?u dung cua dong di?n tang C Hieu dien th6 hi^u dung tren tu dien tang D Hieu dien the hi?u dyng tren cupn cang giam Cau 71: Trong mach dien xoay chiau g6m di?n tra thuAn R, cuon day thudn cam L va t\ dien C mic n6i tilp Liic dau, mach c6 tinh cam khdng, nh giam thn s6 cua dong di?n mgt lugmg nho (sao cho tin so van nho han gia tri ^)thi 27tVLC V A T LY - IIJM T A I li IHUYgT W A B A I T A P T R A C WSHlgM - T A P CHItlfHB 3: OdHB fllgH XOAY CHlgO TAP A dung khang giam B cam khang tang C t6ng tra cua mach tang D t6ng tra cua mach giam Cau 72: Cho mpt doan mach di?n xoay chik AB g6m R, L, C mac noi tiep CO R = 200Q D§t vao hai dhu doan mach mot hieu dien thS xoay chigu CO gia tri hi?u d\mg 220V va tan s6 thay d6i dugc Khi thay doi thn s6, cong 17? tieu thv c6 thS d^t gia trj cue dai bang suat C.242W D 484W Cau 73: Mpt doan mach khong phan rJianh g6m dien tra R, cugn day thuSn cam L v^ tu di?n C mac noi tiSp Mac doan mach tren vao dien dp xoay chik hinh sin thi di?n dp tiic thai a hai dau d o ^ mach cung pha vai cucmg d^ dong dien mach Kk luan ndo sau day khong dung? A He so cong suat cua mach dat gia tri cyrc dai B Cam khang bang dung khang C Dien dp hi?u dyng a hai dau cugn day L va hai dau dien tra R bang fD Di?n dp hieu dyng a hai dau^dogn mach va hai diu dien tra R bang Cau 74: Dung khdng cua mgt m?ich RLC mic noi tiep dang c6 gia tri nho han cam khang Muon xay hi?n tugng cgng huong dien mach ta phai A Tang di?n dung cua tu di?n B Tang h? s6 tvr cam cua cugn day C Giam di?n tra cua mach D Giam tan so d6ng di?n xoay chieu Cau 75: Chgn cau dung Mgt doan mach RLC mic noi tilp, cugn day thuan cam Biet ring dien dp hi?u dyng a hai dau cugn cam L va hai dau tu dien C bang Dien dp tiic thai gifta hai dau doan mach va dong dien mach A cvmgpha B sampha C trepha D vuongpha au 76: (Be thi dai hpc nam 2007) D$t hi?u di?n thS u = 100>^ sinlOO;rt (V) vao hai dau doan mach RLC khong phan nhanh vai C, R c6 Ion khong d6i va L = — H, hi?u di^n th6 hi?u d\mg or hai dhu moi phin tii A.200W B.220V2W g R, Lva C CO dg Ian nhu Cong suat tieu thy cua doan mach la A.350W B.100W C.200W D.250W Cau 77: Mgt doan mach gom di?n tra R, cu^n clay thuan cam c6 dg t\ cam L va tu di$n c6 di?n dung C = 15,9 // F mdc noi tiep Mac mach dien vao nguon (220V-50HZ) thi di?n dp hi?u d\mg R Id 220V Gid tri cua L Id A.0,318H B.0,636H C 0,159H D 0,468H 173 CHIflflie3:DimBDlEllKDAYCHlgU » A T I t » - H M TAT it THDYfT » A BA» T A P TBAC M B g l l - T A P Cau 78: Doan mach noi tiSp c6 difn tra thuan R, cupn day thuan cam c6 tu cam L = -0,4H va t\ di?n c6 di?n dung C = 10"^ F D8 di?n ap hai dhu ^ doan mach cung pha voi di$n ap giiia hai dhn dien tra R thi tan s6 dong dien C O gia tri A lOOHz B 75Hz C 50Hz D.25Hz Cau 79: (De thi cao dSng nSm 2008) Dat mpt hi?u di?n thg xoay chik c6 tan so thay doi ducrc vao hai dau doan mach RLC khong phan nhanh Khi , r tan so dong dien mach ion hern gia tri "^^J^^^y^^ A Hi$u dien the hi?u d\ing giura hai dau di?n tra bang hi?u di?n the hieu dung giiia hai dau do^n mach B Hieu dien thi hi?u dyng giura hai dau cupn day nhd hom hieu di?n the hi?u d\mg giiia hai ban t\ di?n C Dong di?n ch^y doan mach cham pha so voi hi§u di?n the giura hai dau doan mach D Hi?u di?n the hi?u d\mg ^iiia hai dau di?n trd Ian hom hi?u difn the hieu dimg giiia hai dau doan mach? Cau 80: Doan mach RLC n6i tiSp voi ampe dugc mac vao di?n ap xoay chieu u = 200cos(1007rt) (V) Cho biet mach c6 hi?n tugmg cpng huong di?n va so chi cua ampe kS la 2A Gia tq cua R la A lOOfl B.50Q C.50V2Q D lOOVZQ Cau 81: Mach di?n g6m RLC noi tiSp vao mang di?n xoay chiSu c6 di?n ap u =Uocosa)t(V) Cho hik = lOnrad/s va 0)2 = 160nrad/s thi cucmg dg hi?u d\mg mach nhu Tinh gia trj cua (o dl cucmg d? dong di?n qua mach c\rc d^i A 17071 rad/s B 85 TT rad/s C S O T T rad/s D.407r rad/s Cau 82: Cho mpt doan m^ch g6m di?n tra thuSn R, cupn day thuan cam c6 25 , tu cam L =—H va t\ di?n c6 di?n dung C =—}iF n6i tilp Hi?u di?n 7t 7: thS hi?ut\difnghep ghep thedoan va gia l$chdjnhC^iF.c6sobao thuc udi?n thS giua hai dau bO chieu datC'song nao mach trj cua 7i/2 voi hi?u D6 xoay A phai hai dau song mach 6n75/71 vabangbieu nhieu?= Uosin(1007rt) thi the vao hai dku C, C = pha IT/I I AT lY W - m f CHinniB3:DdMEBlilX0AYCHl£u TAT lY THUYgT » A BAI T A P T B A C MfiHlgM - T A P B ghep C'n6i tigp C, C = 75/n ^iF C gh6p C'song song C, C = 25 ^F D ghep C'noi tigp C, C = GO ^iF Cau 83: (De thi cao dSng nam 2008) Mot doan mach RLC khong phan nhanh g6m di?n tra thuan lOOQ , cuon day thuan cam c6 he s6 tu cam L =—H va t\ dien c6 di?n dung C thay doi dugc Dat vao hai dau doan 71 mach di?n hi?u dien the u = 200V2cos(1007rt) (V) Thay doi dien dung C cua tu dien cho den hi?u di?n thS giiJa hai dau cuon day dat gia tri c\rc dai Gia tri cue d^i bang A 200 V B 1OOV2 V C 50V2 V D 50 V Cau 84: Cho hai doan m^ch khong phan nhanh: i?,i^C, va/Jj^jC^co tan s6 rieng dh\i bang/o Khi mac noi tilp hai doan mach thi tin s6 rieng cua mach la A / B.3/0 C /o D 0,5/0 • BIEN THIEN R, L, C Cau 85: (De thi dai hQC nam 2008) Doan mach di?n xoay chieu gom bien tra R, cuon day thuSn cdm c6 t\ cam L ya t\ di?n c6 di?n dung C mac n6i tilp Bilt hieu di?n thg hi?u dun^ hai diu doan mach la U, cam khang ZL, dung khang Zc (voi Zc ZL) va tan so dong di?n mach khong d6i Thay doi R dSn gia trj Ro thi cong suit tieu th\ cua doan mach dat gia tri cue dai Pm, do: A.Ro=Z,+Zc - ~ U C P =— D Ro = ZL-Ze " Ro Cau 86: Mot dogn m?ch khong phan nhanh gom tu di?n c6 dien dimg C = ——F va bien trd R Mac vao hai dau doan mach mpt di?n ap xoay chiSu (220V-50Hz) Dieu chinh hikn tra de cong suat tieu th\ Ian nhat thi gia tri hien tra la A.100Q B.50Q C.120Q D.150Ci 175 CHIflftlG8:DftHeBiei«XflAYeHlgU tfAT DitT L t Z - TIJM T A T tY THUTfT VA B A I T A P T B A C WBHIgM - T j P B 200 V C 100 V C= D OON/2 V B L = — H v^U = lOOV C.L=-HvaU=150V D L = — H v a U = 150V n • n 10"^ Cau 89: Mpt mach di?n xoay chieu noi tilp gom t\ C = F, cupn day 2n thu&i cam L = Hva bien trd R Dat vao hai dau doan mach hi?u di?n thS u = 200COS (lOOTTt) m.Thay doi R de cong suat mach c\rc d^i Gid trj cua R va cong suat luc Ian lugrt la 250 A 120a va — W B.nOQ va 250W 250 C.280t}vd250W D.280nva—W Cau 90: Mpt m^ch di^n xoay chieu khong phan nhanh gom cupn day (c6 di|n tr6 thuan Ro = lOn dp ty cdm L = y ^ H ) , ty di?n c6 di?n dung 10-^ C = — v a di?n tro thuan R thay doi dupe D|t vao hai dau do?in m^ch hi?u di^n the xoay chieu u = 100>/2cos(100;rt) (V) Cong suat tieu th\ tren doan mach d^t gid tri cvrc dai R c6 gid tri: TAT LY THUYgl VA BAl TAP TBAC WGHIEM - CHlfltHB 3: BflHS DlEll XjmHjgB TAP F va dien tra thuan R thay d6i dupe Dat vao hai dau doan mach 71 Cau 88: Cho mach xoay chieu khong phan nhanh g6m dien tra thuan R (thay doi dugc) va cupn day thuan cam c6 dp t\ cam L Hieu di?n th6 hai dau mach u = Uyfl cos(l OOTrt) (V) Bik rang R = 180ri va R = 3200 thi m^ch tieu th\ cung cong suat P = 45W Gia tq cua L va U la A L = - H v a U = lOOV TOM Cau 91: Mot mach dien xoay chiSu khong phan nhanh gom cupn day (c6 dien tra thudn Ro = 30fi, dp tu cam ^ = y ^ H ) , ty di?n c6 di?n dung Cau 87: (De thi cao dSng nSm 2010) Dat difn dp u = f/VZcos (cot) (V) vao hai dSu doan mach gom cupn cam thuSn mic n6i tiep voi mpt bien tra R iTng voi hai gia tri Ri =20 Q va R2 = 80 Q cua biSn tra thi cong suat tieu thu doan mach d8u bang 400 W Gia tri cua U la A 400 V lY Z - f CO hieu dien the xoay chieu u = 100V2cos(1007xt) (V) Cong sudt tieu thu tren R dat gid tri cue d^i R c6 gid tri: A IIOQ B 78,1Q C 50Q D.'l48,7fi Cau 92: Mot doan mach xoay chiSu khong phan nhanh g6m cupn day (dien 02 tra thuan r = 15n, dp tyr cam L = — H) va di?n tra R thay doi dupe Dat vao hai dau doan mach mpt di?n dp xoay chiSu c6 tan s6 50Hz DiSu chinh R dl cong suat toa nhi?t tren R Ion nhat, gia tri cua R la A 15Q B i o n C.25Q D.40Q j:au 93: (De thi dai hH8DlC»HAYCHig| >/2 cos(l ; r r So sdnh I va r, ta c6: A.I = r B.I=/'>/2 C K F va D.I>F 179 CHIftfHE 3: DdNG OIEN XOAY CHlgU yJT L » I Z - T J M T A T LY THUYfT VA BAI TAP TBAC « G H I £ M - TAP • CAC DVNG CV DIEN Cau 104: Chon cau diing Nguyen tic hoat dpng cua may phat dien xoay chieu mot pha, may phat dien xoay chieu ba pha, dong ca khong dong bo ba pha, may bien ap dya tren: A Viec su diang tu tmcmg quay B Hien tugng cam ling di?n tir va sir dung tir truofng quay C Hien tugng cam ung di?n tu D Hien tugng tu cam Cau 105: Roto cua may phat dien xoay chieu c6 cjp cue, quay vai toe 720 vong/phut TSn s6 cua suk dien dong la A.50HZ B lOOHz C.60Hz D 120Hz Cau 106: Roto cua may phat dien xoay chi6u c6 cap cue, tan so cua dong dien la 50Hz T6C dg quay cua roto la A 12v6ng/s B.10v6ng/s C 20v6ng/s D 24v6ng/s Cau 107: Trong cac cau sau day, cau nao sai? A May phat di$n xoay chieu hoat dgng dya tren hi^n tugng cam ling difn tu B May phat di?n la thiet bi bien d6i ca nSng dien nSng C Moi may phat di?n deu c6 hai bg phan chinh la phan cam va phan tao tu truang D Mgt cac each tao suat di?n dgng cam ung may phat dien la tao tir truang quay va cdc vong day dSt c6 dinh Cau 108: So v6ng tren cugn sa cap va cugn thii cSp Ian lugt la 300 vong va 2400 vong Khi may hoat dgng, neu dong di§n chay cugn sa cSp la 18A thi dong dien chay cugn thii cSp la: (bo qua sy hao phi difn nSng) A 2,25A B 144A C 5A D 14,4A Cau 109: Mgt may t§ng the ly tuong c6 ti s6 vong day giiSa cac cugn sa cap Ni va thu cap N2 la Bik cuong dg dong dien cugn sa ckp vk hi?u dien the hi?u dung giura hai dhi cugn sa c^p \hn lugt la Ii = A v^ Ui = 120 V Cuong dg dong di?n hi?u dyng cugn thu dp va hifu di?n the hi?u dung giiia hai dau cugn thu cap ihn lugt la A.2Ava360V B 18 V va 360 V C.2Av^40V D 18Av^40V LY - TdM TAT lY THUYfT VA BAI TAP TBAC WGHlgM - TAP CHlTdNG 3: DdNG DllN XOAY GHI^U Cau 110: Dieu nao sau day la khong dung noi ve dong di^n xoay chigu ba pha? A Cac dong dien xoay chi^u he thong dong dien xoay chieu ba pha phai dugc tao tir ba may phat dien xoay chigu mgt pha B Dong dien xoay chieu ba pha c6 cac dong di?n xoay chieu mgt pha lech pha goc ^ « C Moi dong dien xoay chieu h? th6ng dong di?n xoay chieu ba pha dhu c6 cung bien dg, cung tan s6 D Dong dien xoay chi^u ba pha la h? thdng ba dong di?n xoay chieu mgt pha Cau 111: Phat bilu nao sau day la khong dung noi ve ciu tao va nguyen tic hoat dgng cua may phat di?n xoay chilu ba pha? A May phat di?n xoay chieu ba pha hoat dgng dya tren hien tugng cam ung dien tir B Stato gom ba cugn day gi6ng nhau, b6 tri l$ch 120° tren mgt vong tron C Cac cugn day cua may phat di?n xoay chiSu ba pha c6 the mSc theo kieu hinh hoSc hinh tam giac mgt each y D May phat di?n xoay chieu ba pha la dung cu biln dien nSng ca nSng Cau 112; Chgn cau sai A Dgng co khong dong bg ba pha bien di?n naiig co nang B Dgng co khong d6ng bg ba pha ho^t dgng dya tren co so cua hien tugng cam ung di?n tir va su dung tir truang quay C V$n toe goc cua khung day luon nho hon van toe goc cua tir truang quay D Dgng co khong dong bg ba pha tao dong dien xoay chilu ba pha au 113: Trong dgng co khong dong bg ba pha, tir truang quay dugc tao ig each: A Cho ba dong dien mgt pha vao ba cugn day 11 11 CWlMMS3:Dtll8PlgimYCmgl B lY tt - W*T I t K - Tim TAT LY THDYgT VA BAI TAP TRAC leHlgM - T A H Cho dong di?n ba pha vao ba cuon day gi6ng dugc bo tri lech 1/3 vong tron Cau 114: Ve cau tao, stato cua dong ca khong d6ng bo ba pha gom: A Ba nam cham vTnh cuu bo tri lech 1/3 vong tron B Ba cuon day gi6ng q u ^ tren ba loi sit b6 tri lech 1/3 vong tron C Ba nam cham di?n bo tri lech 1/3 vong tron D Ba cuon day giong quan tren ba loi sit b6 tri lech 1/3 vong tron va mic n6i ti6p vai Cau 115: Trong cac cau sau day, cau nao sai noi \h may bien ap: A Khi may giam thS boat dong thi di?n ap hai dau cuon sa cip Ion han dien dp hai dau cupn thu cap B T i s6 giiia hi?u di?n the hi?u d\mg cua cupn thu cdp va cugn so cap Cling la ti so so vong day cua chung C Goi U i , I i , U2, h Ian lugrt la dien ap va cuong dong di?n hieu dving cupn sa cap va thu cip thi ta luon c6 U,I,=U2l2 CUd»6 8: D t M Diew KOAY CHlgB C G i ^ hi?u di?n thS truyen tai dk gidm hao phi qua trinh truyen tai D Tang cong suat truyen tai Dung dpng ca dk quay mpt nam cham hinh chu: U ben dpng ca C Cho ba dong dien mpt pha vao mot cuon day D m TAT Lf TWYgT WA l A l TAP T I A C tm» - TAP [pau 118: Chpn cau sai Trong mpt may bien the, neu b6 qua hao phi di?n ag cua cac cupn sa cap \h thur cap thi: A May bien the ^ ^ g hi?u di?n t h i bao nhieu \m thi cuong dp dong di?n giam bay nhieu ISn va nguoc lai B May t h i c6 tac dving lam tang cu6mg dp dong dien a mach thii cip C NSu s6 von^ day cupn thur cap Ian hem so vong day cupn sa cap thi may bien the d6 gpi la may tang thg D Di?n ap lay tang bao nhieu Ian so vai di?n ap dua vao thi cong suit ciing tang bay nhieu l i n Cau 119: Trong qua trinh t r u y k tai di?n nang Hieu s6 chi cua cong ta di?n a tram phat va a nod thu sau m6i dem chenh l?ch 480KWh Cong suit hao phi dpc ducmg la ? A.20kW B.40kW C 83kW D lOOkW Cau 120: Mpt dpng ca khong dong bp pha c6 cong suit 3960W dupe mic hinh vao mang di?n xoay chieu ba pha c6 hieu di?n thS gifta hai day pha la 190V, he s6 cong suit dpng co bang 0,8 Cucmg dp dong dien hi?u dung chay qua tung cupn day cua dpng ca la D May b i l n ap la thiSt bi hoat dpng dua tren hien tugng cam ung dien tir, dung de tang hoac giam dien ap A lOA B 12A C 15A D 20A Cau 116: Chon cau dung Gpi N i la so vong day cua cuon sa cap, N2 la s6 vong day cupn thur cip va Ni < N2 May bien the c6 tac dimg: A Tang cuong dp dong di?n, giam hi?u dien thS B Giam cuong dp dong di?n, tang hi?u di?n t h i C Tang cucmg dp dong di?n, tang hi?u di?n the D Giam cuong dp dong dien, giam hieu dien the Cau 117: Chpn cau diing Trong qua trinh truy6n tai di§n nang, may bien the CO vai tro: I A Giam di?n tra cua day dan B Tang hi?u di?n the truyen tai de giam hao phi qua trinh truyen tai 183 CHinrNG 8: DdMG mtn XOAY CHlgP V A T 11? « - TiU T A T LY THBYfT V A BAI T A P T B A C W E H I E M - T A P DAP AN BAI TAP VA C A C C A U H O I T R A C NGHIEM CHirONG III CHIfdNG 3: B A N G DIEN X B A Y CHI^U VAT lY 12 - TdM T A T LY T H U Y £ T V A BAI T A P T B A C MEHlgW - T A P Cau 14: 100V2 = U^f2 cos (IOOTT + | ) => [/ = 200K Cau 15: Bai tap : 300 300 • u = 0,5f/o => cos(1007rt) = ^ Cau 10 Dap an D A A A D C D D A D Cau 11 12 13 14 15 16 17 18 19 ~ 150 k 150 20 Dap an •A B D A C C D C A • 0< i = I = ^=1A=^ Cau 17: i' Cau 4: Suat dien dong eirc dai: EQ = ^QCO = 2V Cau 8: /Q = 3V2.4 Cau 9:u = sin (lOO;it + ^ ) (V) fIOOTT — - - ) \0 =/VI / = 4/1,6J = ^ Cau 12: r = — = 0,02s; t = -= i = COSCIOOTT = 2V2cos(l00rr.^) " = -2007rV2sin(l007r.^) < Cau 18: Trong chu k i dong dien bang khong Ian T = 0,02s; A t = I s = 50T -> so Ian ( i = 0) la 100 lan Cau 19: = lOOViK = ^ ; r = ^ = 0,02s A t = ^ ^ U2 = f/o j=A I = IOOTT r a d / s 0,005s Cau 13: Su dung bai toan tinh thai gian dao dong dieu hoa: (Thai gian ng^n nhat vat dao dong tir v i t r i x = + A den v i t r i A „ ' ' " x = + - l a - ) = '-^ = 0,5A 150 = V2/l -f/n 0,005) = i = lA = lo=>t = l:i + i = yplA va dang giam (dao ham nho han 0) 0) t = +— = 100V2F = L Cau 10: / = ^ = SOHz; T = y = 0,02s; IQ = lA ^ I = Cau 11:/o 400 150 k ^ • =^=3A = 0 ^ cos cos(1007rt) = _1_ t(mm) - — S 400 V=^) Eo = NBSco = 40,2V Cau 5: Bieu thuc suit dien dong: e = 100 400 Cau3:co = 3000 vong/phiit = 3000x — = 100;irad/s; 60 - -^s 300 Cau 16: C Cau : Tir thong cue dai: (^Q = NBS = 0,54Wb tt = -^s; Cau 20: U i = 0 V K = ^ ; T = — = 0,02s C O At = — s = 300 U2 =-100V2V^ ^ 185 CHi/dH6 3: DdiiB mtn XBAY m ly n - liu THOYgj vA L — mt» TAT I Y -200V21/ BAI TAP TBAC IIBIUEM - TAP I ^ — • • -IOOV2/ +200V2K •H • -\-lQQ^[2V ° Bai tap 2: Cau Dap an Cau Dap an Cau Dap an Cau Dap an B 11 D 21 C 31 A D 12 D 22 B 32 A B 13 B 23 B 33 B A 14 B 24 C 34 D D 15 D 25 C 35 A D 16 B 26 B 36 A A 17 B 27 C 37 A 10 C C c 18 A 28 B 38 D 19 C 29 B 39 D 20 B 30 B 40 B Caul:U = IR= IIOV2V Cau 2: • Doan mach chi c6 cac di?n tra thuSn mSc noi tiep, tuang duomg vai doan mach chi c6 mot dien tra thu§n nhSt vai dien tra bang tong cac dien tra thuSn R = Ri + R2 • /oi = /02 = = 2V2 (A) -> Cau D sai Cau 4: Mach chi c6 R u cung pha vai i i = Y = V2 cos (lOOTTt -1) Cau 5: 12 - TiM TAT Lt TBIYfT » A BAl TAP TBAG BSHlgH - CBIDMG 8:BiW6Bl£l«IAYCIIig| • — + —= -4= + ^ = >/2->CauBdung • Mach chi c6 R => u cung pha vai i u = Uocoscot i = locosoyt => — - - = -4= cos(cot) — = cos(a)t) = -> Cau C dung + 4- = 2cos' (wt) -> Cau D sai • TT2 I2 Cau 8: Mach chi c6 L => u som pha — so vai => q)i Cau 9: Mach chi c6 L u sam pha - so vai => = —- z z = -cos(a;t )=-cos(a;t ) Cau 10: • S6 chi cua ampe ke la cuang dong dien hieu dung: I = 2A • Uo = 200V; lo = 1V2 = 2V2A • Lo) = ^ => L lOOrr = ^ L = 0,225// • Zi, = L6J = lOOQ; Io= — = 2,2V2A /o 2V2 Cau 11: Mach chi c6 L => u sam pha - so vai i=>(Pi= (A) • — ^ = 4=—|= = 0->Cau Adung TAP Cau 12: i = 2,2V2 cos (lOOrrt -1) {A) 7t • Doan mach chi CO C=>i sam pha hem u mot goc —=> V UQCO) • Cuomg dong di?n hi?u d\ing: t =J^ = ~vf~ _ •t r -2 CHI/dNG 3: DdNG O I C N X O A Y CHlf U VAT LY - T i M T A T lY THUYfT VA BAI T A P THAC WeHieilll - T A P Cau 13: • Doan mach chi c6 C ==> i som pha hon u mot goc ^ • Cuong dong dien cue dai: /Q = — = UQCO) • Bieu thuc cuong dong dien: t = t/oCw cos {oit + Cau 14: ~ Z C = ^ : = 0 Q ; I O = H L = 2,2V2A Ceo • Mach dien chi c6 tu C, dong dien i som pha hon dien ap mot • BiSu thurc cucmg dong dien: i = 2,2V2 cos (lOOTit +1) (^4) Cau 15: • Zc = ^ = 40fi;[/oc = /o2c = 400V2l' • Mach dien chi c6 tu C, dien ap u tre pha hon dong dien mot , 71 lY Z - T d M T A T l« THBYfT V A BAI T A P T B A C WGHIEM - T A P Cau 24: Cac dap an A, B va D deu sai xet vg pha giua dong di$n va dien dp Cau 26: • • Zc = ^ = n ; / = i2 + H!=*/o = 5/l • Mach chi c6 tu C: - (p^ = - - (pi = - • Bieu thuc cuong dp dong di?n: i = cos (lOOnt + ^ (A) Cau 19: • Z, =Lco = 20Q; Zc= — = 100Q Ceo • Tongtra: Z = ^ R ' + ( ^ - Z ^ ) ' =100Q Cau 20: U = ^U^ + {Ui - UcY = 40V = Loj = 200aZc = ;^ = 100 -> z = ^R^ + (z^ - Zc)2 = looVIa Z V2Z Cau 27: U = ^/W+Ul => U„ = ^U^ Cau 28: • /? = Zi, = Zc = = lOOQ - Ul = lOVZK ^ 0,05 = 2.SA • vi Zi = Zc => z = /? = looa Cau 29: / = Cau 30: UR=^=^UC=> tancp = 71 goc-=*(p„=-• Bieu thuc dien ap: u = 400V2 cos (lOOrrt -1) (V) Cau 17: CHlfflHB : DflNE D | £ N XOAY CHlgU 7t n = l=>(p = - > Suy ra, i tre pha - so vai u Cau 31:

Z, = 100V3i2-*L = ^ = f (//) Cau 34: Z = J = lOOfi u tre pha — so vai i => mach gom tu di?n va cuon day thuan cam, Zc > Zi Cau 35: • DQ lech pha:

/? = lOOQ • Cau 36: • CBlfBlIB 8: B B M SfliEWXBAY CHlgB cos Z = — = a Z c = lOOQ -> Z = 80Q,/Q = v = 2V2/1 Cau 4: Zc = — = lOOfi; Z = ^R^+Zl • i = 2V2 cos (lOOTTt +1) = lOOVfn (i4) / = ^ = V2>i;P = /2i? = 0 V / Cau 37: • Z = 7^=50V2Q; < = (p„-

u som pha hom UR mot goc ^ Cau 13: • P1P2 = Z^ = 100^ (1) Uci = 2yc2 => /i = 2/2 => Z2 = 2Zi P2 = 4Pi (2) Giai he hai phuomg trinh (1) va (2), ta c6: Pi = 5on,P2 = 200a Cau 14: I1Z L - Z C )=2 = RIR2 = 4A; l = f = ( = • Cau 15: PjPz = (Z^, - Zc)^ Bai tap 7: Cau Dap an C D = 3^ P2 = Q C C B ' A CHlftfHS 3: DdHEDlEHXOAY CHlf Hni 12 - TiM TAT it IHUYfl V A BAI T A P TRAC HEHlgM - T A P V A T lY 12 - TIJM TAT lY THUYgT V A BAI T A P TRAC HEHIgM - T A P • Cau 1: AAOB vuong tai O, duomg cao OH Ap dung he thuc luomg tarn giac vuong ABKO vuong tai K: BK Zc tanBOK = - = -^ =^R = Zc = 20on O 0H2 = HA.HB = H A ( A B - H A ) Ui = U L ( U c - U j = R = ZL(Zc-ZL) Cau 4: ^AOB vuong tai O va c6 duomg cao OH OH^=HA.HB U Cau 5: Cau 2: Do lech pha cua Uj so vai u la (p= AAOB vuong tai O va c6 duomg cao OH fa+— ^) • OH^ AOHA vu6ngtaiH: u OA=-^=20H; n cos — AH = H t a n | = 0HV3 • HB = AB - AH = V30H HB V30H OH OH ^ / u r • mR = mi = IQA \ /-V AAHO vuong tai H : tanAOH = OH / i Cau 3: • u 'AN R • AB = Uc = V3Ud = V30A = 2V30H tana = OA^ V 1' OB^ u'MB CHIfflwe3: DdNGOl|NXDAYCHl£u CHl/tfWE 3: ndWB BieilXBAYCmgll WATLtlt-TtllTATtf THBYgT VA BAI T A P TRAC MGHlf M - TAP Bai tap 8; y T L Y 12 A TBM TAT IJ T H U Y £ T V A BAI T A P T B A C NEHIgM - CHlfdNG : DdNG OllH XOAY CHlEO TAP C a u 19: Cau Dap an C A B C A B A C A C Cau 11 12 13 14 15 16 17 18 19 c D B A C C B A B C Cau 21 22 23 24 25 26 27 28 29 30 Dap an C D B B B B B B D A Xet thai diem cam ling tir Bi(max) = BQ 20 Dap an • 10 , Khido • B = Bi -\- B2 + B^ • Cau 3: / = — = SOHz ' Cau 4: / = 60 60 np 60 Vecta cam umg tir t6ng hop tai O: Do Ian cam ung tir t6ng hop tai O: B = B, + IB21 cos 60° + IB31 cos 60° = n =^ = 750i76n^/p/iut Cau 5: / i = /2 => n^Vx = niP2 =» n2 = 450 Cau25:^ =^ = > ^= N2 vbng/phut U2 100 C a u 26: ^ = ^ N2 Cau 10: Ua = ^fSUp = 381V U2 = 20K i^=.f/2 Uz ^ ^ = 2200 vbng C a u 21:H = ^=^P2=Pr.H = UOW Pi C a u l l : / d = V3/p = 17,3i4 Cau 12: Ta thdy 220 = 127V3 nen dien ap a hai dhu mot pha ciia dong ca bang VS Ian dien ap gifta hai day pha mang dien chon dap an D C a u 28: ^ 0 % = ^ ^ £ ^ 0 % = 2.5% C a u 29: Phj, = ( - ^ ) R = 16S3W \Ucos =>(p = • i = 3,53 cos (lOOTTt -1) iT lY 1Z - T A M TAT LY THUYfT tfA BAI T A P TRAC NBHltM - T A P CHtffllie 3: DftUB BltW XOAY CHlgU 600 Cau 9: i = 0,5Io => sinlOQ-rrt = 0,5 300 t = -^ + ^ \0 300 < t < , s - t = ^ s h o a c t = J^s Cau 10: • Doan mach chi chua dien tra thuSn R =» u cung pha i Cau 11: U = UR = IR = 200V Cau 12: 1 ^ CM C2Ttf , I = Ji = - ^ ^ = I^«^i^=>ItilethuanvaiC Cau 13: ^/2 V2Zc V2 1 Ceo C27:f i = Jo = - ^ = Ho^2^^tangflen4ianthiItang4mn ^/2 V2Zc Cau 15: • Doan mach chi c6 lQRcos{cot) V2 R • Khi thay R bSng ty C: lo = u cung pha i U u= UQCOSCOI I R = - r V - = IQRCCO /Co • Doan mach chi c6 tu C: i sam pha ^ so vai u RlQ(ji)Ccos(a)t + ^^ = i= Cau 16: • Doan mach chi c6 R => u cung pha i =» u = /oi/?cos(wt) 203 CHIMBS : DftHB m^K XBAYCHlgB V A T L Y n - TiM T A T L Y THOYfl V A B A I T A P T B A C MeHlgM - TAp i R • Dat dien ap vao hai dhu R2: i = lY - TiM T A T It THBYfT » A B A I T A P T B A C IIBHigM - T A P I C H I W I I : BtllB BitII H A Y CHI^B 71 ' °' cos(Qt) Cau 22: uc tre pha so vdi i ; UR cimg pha i = ^ uc tre pha hon UR mot R2 Caul7: IR = • Dat dien ap u vao hai dfiu cuon day thuan cam L - loCOSCOt ZL => U = RIQCOS goc - • (tot) Cau 23: COL u tre pha ^ so voi i => (p = Doan mach chi c6 L i tre pha ^ so voi u tan li — coL -•mach c6 tinh dung khang cos ^cot-^^ •Cau B sai R 3j Cau 24: 2/ \ Cau 18: ; ZL=L27rf; Z.= Z= R^ + L27tfC27rf J C27if I o = - ^ = UoCco Tang tan s6 f: Dung khang Zc giam, cam kMng Z L t3ng, di?n tra R khong doi, tong tra Z thay d6i 7t Doan mach chi c6 tu C => i som pha — so vai u i = UQCCOCOS Cau 25: >ZL=L27xf cat + ; Z= R^ + L2nf- C27if C27tf Giam t&n so f: Dung khang Zc tSng, cdm khdng Z L giam, t6ng Cau 19: Z= L(o = 200n, I o = ^ 71 Doan mach chi c6 L => i tre pha — so vol u i = V2< cos 2J tr6 Z tang vi dp 16n L i f - = V2A

m?ich chi c6 L va C nhimg (Z^ < Zc)Cau 27: U = mot goc — tang C27rf Cau 26: =V2.cos ^ O O T i t - - ^ (A) Cau 21: U L som pha - s o voi i ; UR ciing pha i => UL som pha hon UR I / Q C O S (cot) C O S (wt) = — i = /Q cos (wt + f ) = - ^ sin(a)t) = sinayt = > '/o sin^ (Dt + cos^ 6)t = l = > : T + ;7 T = l 1/2 9n» HIS EHIftfHS 3: DflHB PrEll XOAT EHlgy VAT Cau 28: u = Uo cos(ajt) • U I 1 lY 12 - m n im€l TAT VA BAI TAP TRAC WGHlgM - t = /o cos (cot - f) = /Q sin(a>t) = 0=>CauAdiing = 2cos^ (cot) + sin^ (cot) = = ( / Q C O S (cut) = » t /QCOS = • -;7UQ Cau Ddpan Cau Dap an Cau Dap an Cau 31: Mach di?n chi c6 L va C 38 39 D A 48 49 B B 58 59 B C 71 Cau 33: • Zi, = L(o = icon; Zc = ^ = 200n; Z = ^{Zi-ZcY Cau 37: 40 C 50 C 60 C i som pha - nSu Z L < Zc CHtfJHB 8: BflNSfllgKXBAY CHlgli = => Ul = U^-Ul=^Ui = 80K • Z == Leu = icon; ^cY=;?-= son; Zt + - Zc 50V2fl (cut) 37 A 47 A 57 C TAP Cau 36: IQ 36 D 46 D 56 C HGHlgM - Cau 35: y = Vf^JT(yr^yj2 = 130K Cau C dung + -;^ = 4-+4= = V2=>CauDdung V2 V2 35 A 45 A 55 A BAI TAP TRAC Cau 34: U^ = Ul + + ^0 = cos (cot) + cos^(cot) = 2cos^(cot) =>CauCsai — T2 31 32 33 34 A A C A 41 42 43 44 B D C B 51 52 53 54 C A A D tfA THUY^T ZA U I 1 Uo lo 72 V2 u iT" = — ? r = Cau A dung ^ _ i = V2cos(cot) - V2cos(cot) = => Cau B dung u2 Tl2 '-'0 lY 12 - Tl>M TAT LY • Cucmg d6ng di?n hi^u dving: I = - = lA U + -p = -U+4= = V2=>CauDdung lo U ^0 V2 ' V2 Cau 29: u IAT 100ft — - -J = cos^ (cot) - sin^ (cot) ?i => Cau B sai ' + TAP Cucmg d? dong di?n hi?u d\mg I = ^ = V2 A Lit) z = V R ' + - Zc)2 = son • / = ^ = 2^=>f/ = /.z = iooy (ZL Cau 38: • tre pha — so voi u =» = T 4 tan (p =-^t—^ => Z, = 300Q => L = - H Cau 39: • Zi = Leu = son; Z c = ^ = 0 n ; z = ^JR^ + iZi^-ZcY = loon /„=^=2^;tan^=^=-^.-^ =- f • L = — H • Zi = Lo) = 50n;Z = + 2f = loon - • i = cos (lOOnt -1) (A) V A T LY - T O M T A T LY T H U Y E T V A B A I T A P T B A C WEHIgM - T A P CHIIdNe : DANG DlEN XOAY CHI^D UL sam , 7t n u som pha — so vai i ==>

a)L < — =» Zi < Zc => i sam pha han u Cau 51 =Lo) = 100Q 71 u tre pha — so voi i ,p = - => = - => Zc = 125fl Cau 52;^ Cau 53; Ul = UQI « V3 V3 1071 cos (a)t +1) => i = /o cos (wt - (vi 71 • UoL = IoZi = 50V • U L som pha so v6i i =>UL = 50 C O S (lOOTTt - f + f) = 50 cos (lOOrrt + - ) (V) ' Cau 43: U R cung pha i => i = IQCOSCJI = — coswt = R pha — so voi i) (/J = 0: mach c6 tinh cam khang Cau 54 : Dap an D Zi = Lo) = lOO; Zc = -^= 20n; Z = lOVIn /Q = =» i = 2V2cos(1007rt)(i4) R Uo = hZ = AQV Cau 45: ^ = - ip, = J tan

=» Z^ > Zc Cau 46: q) = (pu- (Pi=^=> taivp > => doan mach gom cugn day thuSn L \k di?n trd thuin, Cau 47: • Zi = La) = 100n;Zc = - = SOU • ucl?chpha ^ sov6ium^uclu6ntrepha-sovoii H2L = 2V2^ ; U L sam pha ^so voi i u = 40 cos (lOOTTt - J) (V^) Cau 55: = ^ = 8oaz = JWTz^ = loon • cos(p = - = 0,6 Cau 56: F = i//cos

/ = = 0,5^ => « = ^ = 120n mm mto 3: D A N G OIEK X O A Y VATIY I Z - T J M T A T L Y THBYfiyA BAl T A P T R A C N G H I E M - T A P I AP ClltfdNG 3: BdNGflIEWXBAY CHlgU lY 12 - TdM TAT lY THUYgT V A BAI TAP TBAC MHltM - TAP Cau 57: z = V(/? + ry + (Zt - ZcY = loon T s Cau 64: Z, = 50fl -» Z, = 0,5 v i (/2 = (75V2)' H khong thuan cam Cau 58: u^+uj-u^ UR = U^yfS COS(p=^ ^ U 2UL = ^ P = WR + UrV=>I Cau 60: = p = 0,5/1 Cau 65: • = 401^ 2UR = ^ cuon day y| +1/2 = 352 + 852 Z, = L(o = 20il,Zc= ZL=LCO = Q ; Z C = — = 100Q; =100a =^R = 160n; 40fl Co) /? = 160 => Z = SOVSfi =* cos(p = ^ = ^ Z=7R^+(ZL-ZC)^ = 1OOQ — R = 40n => Z = 40V5fi => cos(p = ^ = ^ i=I^=-yi-=:/2^_>P=i^R=3ow Z V2Z Cau 66: Q = I^Rt = Cau 67: UOkJ Cau 61 62 63 64 65 66 67 68 69 70 Dap an A C B B D B C A A A < P R L = f =*7 = V = > Z , = /?V3 Cau 71 72 73 74 75 76 77 78 79 80 Zc=Z, Dap an D C C D A B B D C C Cau 81 82 83 84 85 86 87 88 89 90 Dap an D A A C D A B D A C Cau 68; Khi mach dien xay cong huong: UR = U Cau 69 Mach cong huong: Zc=Zi = L(o = 200n Cau 70 Khi mach xay cong huong: Cau 61: P = UIcos(p = SQy/SW lOOfl; p Cau 71: Cau 63: • Zi, = Lw = 40a Zc=-^= 50 Tang tan so: I giam (cau B sai), U L C6 the tang hoac giam (cau C sai), Uc giam (cau B sai) va h? so cong suit giam (cau A dung) R = iQOW Cau 62: (p = (p^ - (pi =- ^ U • ZL = LO) = son; Zc = ^ = lOOH; Z = SOVZfl • P = I2R = = /?V3 C2Kf > Z , =L27if ; Z = ^ L27tf- C27tf Z11 CHITDHG : Dftme D I E M X O A Y C H | £ B VAT tt 12 - TiM TAT lY THIlYfT VA BAI TAP TBAC Giam tan s6 f: Dung khdng Zc tSng, cam khang HGHlfM - TAP giam, t6ng tra Z giam vi dp Ion |L27tf - - ^ giam C2nf VAT l Y - TflM T A T l Y T H U Y ^ T « A B A I T A P TRAC WGHIEM - 100 Zc^^ =Zi = Lio = lOOn = Qa = —I^P > • Cau 74: C2nf CHlfflWS : DdNG D I E N X O A Y CHlf D • Goi Ctd la di?n dung tuong ducmg cua bp tu C va C Khi mach xay cong huong: Cau 72: Thay d6i f dS P „ ^ => mach cgng hucmg: P^^x = f = 2421^ TAP Ct&> C = —nF =>C' song song C Ct& = C + C' =>C' = -^F > Z L = L2n{ => de c6 hi?n tugng cong hucmg Cau 83: Thay d6i C dk U L ( m a x ) : mach cong huong = L27cf => giamtansof C27rf Cau 75: = =^=2A^ Imax => U^^rnax) = ImaxZi = Z^ -> mach cong huong => u cung pha i Cau 84: Tan so cua rieng cua mach RLC: f = Cau 76: = 200V 27tVLC Uji = Ui = Uc'=^ R = Zi = ZQ' mach cong hucmg • Theo de bai ta c6: fo, = f^^ => C,L, = C^L^ => CL =-^(1) • P m a = y = |;=100H^ Cau 77: UR = U ^Zi=Zc Khi mac noi tiep hai doan mach vai nhau: L= C,C, = 200n = L = 0,636// > Cau 78: • U R cung pha i ma u cung pha U R => u cung pha i cong hucmg • Tan so dong di^n mach mach _C,C,(Li+L,) Xet: LC = (2) c,+c f = \ = 27tVLC Cau 79: / > xay cong hucmg: Thay (1) vao (2) ta dugc: LC = L i Q = / = /o > } \ z => Llnf Cau 86: >^ => Z^ > Zc: i cham phahon u Cau 80: /? = y = SOVIn R = Zc=-^ = loon Cau 87: p = R1+R2 U = 200K! Cau 88: 2,4 Cau 81: w = V ^ i < ^ = 407r rad/s Zf = R^R2 => Z|, = 240n =>L = =^H Cau 82: • • u l?ch pha ^ so vai uc huong u cung pha vai i mach cong P = R1+R2 =^U = ISOV Cau 89: z^ = Lw = son; Zc = -^ = 2oon R = \Z,-Zc\ i2on , p = !^ = ^w Z1Z L1+L2; CHirifKG 3: DdNG OIEM X O A Y CHlfU V A T L Y I Z - T O M T A T L Y THUYf I U A BAI T A P T B A C N G H I £ M - T A P Cau 90: Cau 100: Cach 1: ui vuong pha U = > Ctancpi) (tan^z) = — • Zi = L(x) = 40n; Zc=^ = loon • R + Ro = \Z,-Zc\-^R Cau i 91 92 93 • U A B lech pha — so voi U N B ==> (tan^^e) (tancpf^B) = ~ = Sm 94 95 CHIiaNG 3: DdNG DIEN X O A Y CHlEu V A T lY 1Z - T D M T A T lY T H U Y E T V A BAI T A P T H A C H G H I E M - T A P 96 97 98 99 100 Dap an C C C C C A B D C C Cau 101 102 103 104 105 106 107 108 109 110 = Ul + Ul -2U,Uc Dap an D A C C C B C A A B = Ui + ul - 2(U^ + Ul) + Ul Cau 111 112 113 114 115 116 117 118 119 120 Dap an D D D B C B B D A C R^o + iZL-Zcy Cau 92: Z^ = Cau 93: /? = |Z, - ZcI 08^ = OH^ + HB^ => Ulc = Ul + Ul + Z f = 250 Z = /?V2 • AAOB vuong tai O: AB^ C05(p = j = f Zc = 50Q =^ C = — F 5n = OA^ + OB^ Ul = U^ + Ul + Ul n Cau 96: Z^, = Loj = 20n ; /?i/?2 = Zl => P = Cau 101: • R = \Z,- Zr\ = 300a =^L = - H =^ /?2 = n = 25M^ Cau 98: Zf, = La> = 240 ; /? = Vr^Tzf = 400 Cau 99: /?iP2 = = AB: • AO//B vuong tai H: Cau 95: Zr = — = lOOH ZL • UAS = OA:UI^ 1-3 Cau 94: Z^ = /?i/?2 Cau 97: /? = Cach 2: Dung gian vecta = son = 20fi ; /? = = ul + ul + u^ URC = OB; Uc = HE Cau 91: Z i = Lw = 600; Zr = — = lOOH Cui R = Ul + Ul Zi, = La) = 0 O ; Z c = — = 0 • URL l?ch pha ^ so voi URC = ^ itan^Ri)- (ta" / ? = Z : , Z c = » / ? = 200O R R Cau 102: • U L C luon lech pha ^ so voi i • U L C • ta suy ra: u l?ch pha ^ so voi i - •^c)^ = 50000^ -> Cau A dung P = => /?i + /?2 = ^ -> Cau B dung Rl+R2> 2yfR^ U2 =1000 (;2 => p = i R1+R2 ~ 0 lech pha — so vdri u (theo de bai) Cau D diing 9= ^ CHtftfme 3: DftwG mtn XBAY cmgo VAT LY 12 - TOM TAT LY THuygT vA BAI TAP T A HEHIEM - TAP RC • cos(p = —=:>Z = - ^ = 0 f i ^ I = — - , A Z coscp Z Cau 103: • Ta thdy: o) = co^ = lOO/r rad/s va o) = = 120n rad/s thi cuong dong dien hieu dvmg Ii = I2 = I =^ tan so goc xay hien tugng cong hixong la (OQ = yfco^Oil = 109,Sn rad/s • = IIOTT r a d / s c6 gia tri ghn voi nhdt so vai Wjva =>/'>/ • Luru y: Bien dao dpng tang dan tan so tien ve gia tri xay cong hucmg Cau 105: / = ^ = 60Hz 60 Cau 106: / = ^ => n = 600 ^ = 10 vbng/s Cau 108: ^ = 60 =» /, = 2,25/1 ' p/liit JV2 '1 Cau 109: ^ = i^ = ^ = > [ / = 3601^ = h Cau 119: P = -= lOkW t Ni U2 P = 3UpIpC0S(p =^ Ip = ISA 2A ... 11 0 = Ul + Ul -2U,Uc Dap an D A C C C B C A A B = Ui + ul - 2(U^ + Ul) + Ul Cau 11 1 11 2 11 3 11 4 11 5 11 6 11 7 11 8 11 9 12 0 Dap an D D D B C B B D A C R^o + iZL-Zcy Cau 92: Z^ = Cau 93: /? = |Z, - ZcI... P Cau 14 : 10 0V2 = U^f2 cos (IOOTT + | ) => [/ = 200K Cau 15 : Bai tap : 300 300 • u = 0,5f/o => cos (10 07rt) = ^ Cau 10 Dap an D A A A D C D D A D Cau 11 12 13 14 15 16 17 18 19 ~ 15 0 k 15 0 20... tong hou zo o B, 10 Dap an D D D A B B B B D D 11 12 13 14 15 16 17 18 19 20 Dap an = Cau Vay, 1^ 21 = I B I Cau B A B C B B A D C C CHtfltwe 8: Dime DIEN X O A Y mtV V A T Y 1Z - T J M T A T

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