... v1 = 13 9,8 o C. ⇒ Ct o m 35 ,14 1 2 8 ,13 99 ,14 2 Tra A ở [2], trang 28: t m ; o C 0 20 40 60 80 10 0 12 0 14 0 16 0 18 0 200 A 10 4 12 0 13 9 15 5 16 9 17 9 18 8 19 4 19 7 19 9 ... 16 1677,0 18 3, 01 40 3,0 40 3,0 1 2 OH c NaOH c NaOH c M x M x M x a ⇒ M = 0 ,16 1677.40 + (1 – 0 ,16 1677) .18 = 21, 55689 kg/kmol ⇒ 59,0 55689, 21 25 ,12 73 .25 ,12 73.425,3323 .10 .58,3 ... (I.44), trang 15 2, [1] : a = 18 % (a < 0,2): c đ = 418 6. (1 - a) = 418 6. (1 - 0 ,18 ) = 3432,52 J/(kg.K) a = 30 % (a > 0,2): c c = 418 6 - ( 418 6 - c ct ).a = 418 6 – ( 418 6 – 13 10,75).0,3...