... be found is equal to |λ|√a2+ b2+ c2. Point(x1, y1, z1) lies in the given plane and, therefore,a(x0+ λa) + (b(y0+ λb) + c(z0+ λc) + d = 0,i.e., λ = −ax0+by0+cz0+da2+b2+c2.1.28. ... coordinates of pointsA and B are ( a, 0, 0) and (a, 0, 0), respectively. If the coordinates of point M are(x, y, z), thenAM2BM2=(x + a)2+ y2+ z2(x − a)2+ y2+ z2.The equation ... coordinates of point X be (x, y, z). Then AX2=(x − a1)2+ (y − a2)2+ z2. Therefore, for the coordinates of point X we get anequation of the form(p + q + r)(x2+ y2+ z2) + αx...