... 2 1 1 0, , 1 1 0 2P D = = ÷ ÷ 1 1 1 12 2y xY P X Py x− − = ⇔ = ÷ ÷ 1 (1) ( )Y DY P F t = + 1 1 1 , 1 2P = ữ 1 1 1 2( ) 1 23t tt ... A2 1 1 2 1 1 2 (6 ) 02 4 4A Iλλ λ λ λλ−− = − = − =− 1 206λλ=⇔= 1 ( ) 0A I Pλ− = 1 23 1 1 2 1 1 2 02 4 4ppp ữ ữ = ữ ÷ ÷ ÷ chọn 1 2 1 2 1 , 00 1 P ... ÷− − − 1 1 1 122 2 2 22 22 3 3t t tt t ty y e y te C ey y e y e C e ′= + = + ⇔ ⇔ ′= − = + Vd: 1 1 2 32 1 2 33 1 2 32 1 1 22 1 1 22 4 42 2 4x x...