... = 2 2 2 Φ iin , 2 ΦtgSS 2 21ψ = ,SS 21 2 22= =()= − = −∗ˆˆcos Re ,ˆˆEE E Exy xy x 2 y 2 xEE EΦ EEy 2 .aS S S bS S S 2 01 2 2 22 01 2 2 2 =+ + =− +,.S0 2 2=+= +ˆˆEEx 2 y 2 xyEES3 22 ==()ˆˆsin ... −qgg 2 g 22 1 2 ddω.qzpgpp 2 ωωω ωωωτωωω()= −()= − =−11 2 22 2 2 2cvccp,, 22 3 2 ().τωωπ== =⋅−pcfeNmcNf3 2 3 2 22 3 2 129 2102z z z 2 ..∆FNf=13 63 2 ..zTF1710_book.fm ... statistical character of the problem, the Stokesparameters should be considered as statistically averaged values. Then, (2. 57) (2. 58) (2. 59) (2. 60)SabSabSab0 22 1 22 2 22 2 2 2 2 2=+=−()=−(),cos,sinψψ,,...