Fundamentals of Structural Analysis Episode 2 Part 3 potx

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... example, 3. 028 +.0 03/ 009 has an upper limit of 3. 031 and a lower limit of 3. 019.) 2. Subtract the lower limit from the upper limit to get the total tolerance band. (3. 031 -3. 019=.0 12) 3. Divide ... shown in Figs. 8-1, 8 -2, and 8 -3. Statistical tolerance requirements canbe indicated in the ST frame in one of the three ways defined in sections 8 .2. 1, 8 .2. 2, and 8 .2. 3. 8 .2. 1 Using Process Capability ... professor in the Mechanical Engineering Department at ColumbiaUniversity, New York, NY. He is a member of ASME Y14.5.1 and several of ISO/TC 21 3 Working Groups.He is the Convener of ISO/TC 21 3/ WG...

... candidate processes//SYS21///INTEGRAS/B&H/PRS/FINALS_07-05- 03/ 075065 437 6-CH0 02- 1.3D – 22 3 – [35 24 8 /21 4] 9.5 .20 03 2: 05PM7. 12 BrazingProcess description.Heat is applied to the parts to be joined ... //SYS21///INTEGRAS/B&H/PRS/FINALS_07-05- 03/ 075065 437 6-CH0 02- 1.3D – 22 2 – [35 24 8 /21 4] 9.5 .20 03 2: 05PM.Minimum sheet thickness, commonly:.Carbon steel ¼ 0.5 mm.Cast iron ¼ 3 mm..Maximum ... process.Brazing 22 3 //SYS21///INTEGRAS/B&H/PRS/FINALS_07-05- 03/ 075065 437 6-CH0 02- 1.3D – 21 5 – [35 24 8 /21 4] 9.5 .20 03 2: 05PM7.9 Solid state weldingProcess description.A range of methods utilizing...

... ahead of bevel pinionFig. 7.19 Final drive spur double reduction between crownwheel and differential 24 3 ence in rolling radius of both axles about someinstantaneous centre of rotation. 2 Small ... bearing preload using adjusting nuts 23 2Combining a high and low ratio in the same axledoubles the number of gears available from thestandard gearbox. The low range of gears will thenprovide the ... reduction axlesOutboard epicyclic spur gear double reduction axle(Fig. 7 .22 )Description of construction (Fig. 7 .22 ) A gearreduction between the half shaft and road wheelhub may be obtained...

... approx-imately 32 . 1 739 8 ft/s 2 equal to 33 86 .38 864 034 1impulse sealing[ENG]Heat-sealing of plasticmaterials by applying a pulse of intense thermal pascals; used as a unit in the measurement of atmospheric ... of the thermome-[THERMO]A unit of absolute temperature equalter above 100ЊF (38 ЊC) and noting the time itto 1 /27 3. 16 of the absolute temperature of thetakes to cool from 100 to 95ЊF (38 ... rate of change of accelera-Jaeger-Steinwehr method[THERMO]A refine-ment of the Griffiths method for determining the tion; it is the third derivative of position withCopyright 20 03 by The...

... (Maria) is standing next to her desk. 1. stand up 12. kick your desk (softly) 2. smile 3. whistle 4. open or close the door 5. hum 13. knock on the door 14. sit on the floor 15. shake ... hobbies Take notes during the interview. PARTK Write the names of your classmates on a sheet of paper as they are introduced in class. 17 EXERCISE 2. Introducing yourself in writing. Direcrions: ... 1 -2) Directions: Use the present progressive to describe activities in progress. Work in groups or as a class. FIRST: One member of the group pretends to do something, and the rest of the...

... truss:⎥⎥⎥⎥⎥⎥⎥⎥⎥⎦⎤⎢⎢⎢⎢⎢⎢⎢⎢⎢⎣⎡−−−−−−−−−−−−−−−−80 .37 60.900 .25 080. 126 0.90060.9 53. 400060. 920 .7 033 .33 00 .25 000 .25 0000000 033 .33 033 .33 008. 126 0.90080 .37 60.900 .25 060. 920 .70 33 .33 60.9 53. 4000000000 .25 000 .25 0 033 .33 0000 033 .33 ⎪⎪⎪⎪⎭⎪⎪⎪⎪⎬⎫⎪⎪⎪⎪⎩⎪⎪⎪⎪⎨⎧0004 3 3 2 2uvuvu=⎪⎪⎪⎪⎭⎪⎪⎪⎪⎬⎫⎪⎪⎪⎪⎩⎪⎪⎪⎪⎨⎧−40000.15.011yPPPyxFor ... ⎥⎥⎥⎥⎥⎥⎥⎥⎥⎦⎤⎢⎢⎢⎢⎢⎢⎢⎢⎢⎣⎡−−−−−−−−−−−−−−−−−−−−−−−−80 .37 60.900 .25 080. 126 0.90060.9 53. 400060. 920 .7 033 .33 00 .25 080 .37 60.90080. 126 0.90060.9 52. 40 033 .33 60. 920 .78. 126 0.90080 .37 60.900 .25 060. 920 .7 033 .33 60.9 53. 40000080. 126 0.900 .25 080 .37 60.9 033 .33 60. 920 .70060.9 53. 40Note ... ⎥⎥⎥⎥⎥⎥⎥⎥⎥⎦⎤⎢⎢⎢⎢⎢⎢⎢⎢⎢⎣⎡−−−−−−−−−−−−−−−−80 .37 60.900 .25 080. 126 0.90060.9 53. 400060. 920 .7 033 .33 00 .25 000 .25 0000000 033 .33 033 .33 008. 126 0.90080 .37 60.900 .25 060. 920 .70 33 .33 60.9 53. 4000000000 .25 000 .25 0 033 .33 0000 033 .33 For the second truss:K 2 = ⎥⎥⎥⎥⎥⎥⎥⎥⎥⎦⎤⎢⎢⎢⎢⎢⎢⎢⎢⎢⎣⎡−−−−−−−−−−−−−−−−−−−−−−−−80 .37 60.900 .25 080. 126 0.90060.9 53. 400060. 920 .7 033 .33 00 .25 080 .37 60.90080. 126 0.90060.9 52. 40 033 .33 60. 920 .78. 126 0.90080 .37 60.900 .25 060. 920 .7 033 .33 60.9 53. 40000080. 126 0.900 .25 080 .37 60.9 033 .33 60. 920 .70060.9 53. 40Note...

... trussesshown.(1-a)(1-b)(1-c) (2- a) (2- b) (2- c) (3- a) (3- b) (3- c)(4-a)(4-b)(4-c)Problem 1.3m4m 3 kN3m4m3m8 kN3m4m3m8 kN 3 kN3m4m4 kN3m4m4 kN3m2m6 kN2m1.5m1 .2 m1.6 m0.9 m 2 m2 m1 .2 m0.9 m0.7 ... solved by the method of joint.xy1 2 4m3m 3 3m1 2 3 1.0 kN0.5 kN141 3 4514 32 1 2 3 45 2 14 32 1 3 456Truss Analysis: Matrix Displacement Method by S. T. Mau 29 Kinematic instability ... -0.50 0 .33 2 0. 033 -0. 021 0.60 -1.00 3 0. 029 -0.007 0 04 0.011 0 0 0.67Member Elongation (m) Force (MN)1 -0. 021 -0. 52 2 -0.004 -0.14 3 -0.008 -0.194 0.011 0 .36 5 0. 030 -0.606 0.0 12 0 . 23 Note...