... equation, then solve. For the eleventhterm, k will be equal to 11, so 10 ~k 1 1!k 2 15 10 ~11 1 1!11 2 15 10 ~12! 10 5120 10 5 127. If you do not see the answer by visualizing the points, ... an odd number. Therefore, the answer must be in the 100 0’s. 101 1 is far too less a sum of digits, and 109 9 is too great, but not by much.Try 108 8. It sums to 17.Section 8As you might expect, ... Peterson’s, a part of The Thomson Corporaton SAT is a registered trademark of the College Entrance Examination Board, whichwas not involved in the production of and does not endorse this product. 10. ...