... number of blocks read is 4,0 0 1,6 4 3, which totals 2,0 4 8,8 4 1,2 16bytes or about 1.9 GB.■■ The total number of blocks written is 3,4 2 3,9 8 1, which totals 1,7 5 3,0 7 8,2 72bytes or about 1.6 GB.Performance ... display unit, which defaults to bytes, use -S k for units of1000 bytes, -S K for true kilobytes (1024 bytes ), -S m for units of 1,0 0 0,0 00bytes, or -S M for true megabytes ( 1,0 4 8,5 76 bytes). ... I/O subsystem is performing and iden-tify I/O bottlenecks. For example, the more read and write requests that aremerged (see rrqm/s, wrqm/s, r/s, and w/s ), the more efficient the I/O sub-system...