... left-hand side and the decryption process going up the right-hand side for a 16-round algorithm. Forclarity, we use the notation and for data traveling through the encryptionalgorithm and and ... have= 03A6 and .Now let’s look at the decryption.We assume that and ,as shown in Figure 3.3, and we want to demonstrate that and . So, we start with and .Then, from Figure 3.3, and [F(03A6, ... Reading and Web Sites 47815.7 Key Terms, Review Questions, and Problems 479Appendix 15A Kerberos Encryption Techniques 481PART FIVE NETWORK AND INTERNET SECURITY 485Chapter 16 Transport-Level Security...